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Generalities about surfaces                                       135

                                       2
                Theorem 5.12 Let Ω ⊂ R be a bounded Lipschitz domain.
                                    ¡ ¢           2  ¡  3  ¢
                   Part 1. Let Σ 0 = v Ω where v ∈ C  Ω; R , v = v (x, y),with v x × v y 6=0
                in Ω.If
                                         Area (Σ 0 ) ≤ Area (Σ)

                                                  2
                among all regular surfaces Σ of class C with ∂Σ = ∂Σ 0 ,then Σ 0 is a minimal
                surface.

                   Part 2. Let S Ω be the set of nonparametric surfaces of the form Σ u =
                ©                      ª           2  ¡ ¢
                 (x, y, u (x, y)) : (x, y) ∈ Ω  with u ∈ C  Ω and let Σ u ∈ S Ω . The two fol-
                lowing assertions are then equivalent.

                   (i) Σ u is a minimal surface, which means
                                  ¡    2  ¢               ¡    2  ¢
                            Mu = 1+ u  y  u xx − 2u x u y u xy + 1+ u x  u yy =0 .
                   (ii) For every Σ u ∈ S Ω with u = u on ∂Ω

                                                      ZZ
                                                          q
                                                                 2
                         Area (Σ u ) ≤ Area (Σ u )= I (u)=  1+ u + u dxdy .
                                                                     2
                                                                 x   y
                                                        Ω
                Moreover, Σ u is, among all surfaces of S Ω with u = u on ∂Ω, the only one to
                have this property.
                Remark 5.13 (i) The converse of Part 1, namely that if Σ 0 is a minimal sur-
                face then it is of minimal area, is, in general, false. The claim of Part 2 is that
                the converse is true when we restrict our attention to nonparametric surfaces.
                   (ii) This theorem is easily extended to R n+1 , n ≥ 2.

                   Proof. We will only prove Part 2 of the theorem and we refer to Exercise
                5.2.4 for Part 1. Let

                                   v (x, y)= (x, y, u (x, y)) , (x, y) ∈ Ω

                we then have
                              ZZ                 ZZ
                                                     q
                                                           2
                                                                2
                       J (v)=     |v x × v y | dxdy =  1+ u + u dxdy ≡ I (u) .
                                                           x    y
                                Ω                  Ω
                   (ii) ⇒ (i). We write the associated Euler-Lagrange equation. Since u is a
                minimizer we have
                                I (u) ≤ I (u +  ϕ) , ∀ϕ ∈ C  ∞  (Ω) , ∀  ∈ R
                                                        0
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