Page 61 - INTRODUCTION TO THE CALCULUS OF VARIATIONS
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48                                                    Classical methods

                          Part 2. Conversely if u satisfies (E) and if (u, ξ) → f (x, u, ξ) is convex for
                       every x ∈ [a, b] then u is a minimizer of (P).

                          Part 3. If moreover the function (u, ξ) → f (x, u, ξ) is strictly convex for
                       every x ∈ [a, b] then the minimizer of (P), if it exists, is unique.

                       Remark 2.2 (i) One should immediately draw the attention to the fact that this
                       theorem does not state any existence result.
                          (ii) As will be seen below it is not always reasonable to expect that the mini-
                                                      1
                                      2
                       mizer of (P) is C ([a, b]) or even C ([a, b]).
                          (iii) If (u, ξ) → f (x, u, ξ) is not convex (even if ξ → f (x, u, ξ) is convex for
                       every (x, u) ∈ [a, b] × R) then a solution of (E) is not necessarily an absolute
                       minimizer of (P). It can be a local minimizer, a local maximizer.... It is often
                       said that such a solution of (E) is a stationary point of I.
                          (iv) The theorem easily generalizes, for example (see the exercises below), to
                       the following cases:
                                                      N
                          - u is a vector, i.e. u :[a, b] → R , N> 1, the Euler-Lagrange equations are
                       then a system of ordinary differential equations;
                          - u : Ω ⊂ R n  → R, n> 1, the Euler-Lagrange equation is then a single
                       partial differential equation;
                                 ¡               ¢
                          - f = f x, u, u ,u , ..., u (n)  , the Euler-Lagrange equation is then an ordinary
                                         00
                                       0
                       differential equation of (2n)th order;
                          - other type of boundary conditions such as u (a)= α, u (b)= β;
                                                                           0
                                                                 0
                                                       R  b
                          - integral constraints of the form  g (x, u (x) ,u (x)) dx =0.
                                                                    0
                                                        a
                          Proof. Part 1.Since u is a minimizer among all elements of X,wehave
                                                  I (u) ≤ I (u + hv)
                                                   1
                       for every h ∈ R and every v ∈ C ([a, b]) with v (a)= v (b)=0.In other words,
                                                                1
                       setting Φ (h)= I (u + hv), wehavethat Φ ∈ C (R) and that Φ (0) ≤ Φ (h) for
                       every h ∈ R. We therefore deduce that
                                                               ¯
                                                     d         ¯
                                            Φ (0) =    I (u + hv) ¯  =0
                                              0
                                                    dh         ¯
                                                                h=0
                       and hence
                            Z  b
                               [f ξ (x, u (x) , u (x)) v (x)+ f u (x, u (x) , u (x)) v (x)] dx =0 .  (2.1)
                                                                  0
                                                 0
                                           0
                             a
                       Let us mention that the above integral form is called the weak form of the
                       Euler-Lagrange equation. Integrating by parts (2.1) we obtain that the following
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