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Friction, lubrication and wear in lower kinematic pairs  127

                                 where </> is the angle of friction for the contact surfaces.

                                 Solution

                                 Referring to Fig. 4.31, EA and CA are the common normals to the contact
                                 surfaces at the points of contact E and C respectively. RI and K 2 are the
                                 resultant reactions at E and C inclined at an angle <p to the common
                                 normals in such a manner as to oppose rotation of the shaft.
                                   If R l and R 2 intersect at B, it follows that the points A, B, C, D, E lie on a
                                 circle of diameter AD. Hence


      Figure 4.31
                                 The resultant of/?! and R 2 must be parallel to the line of action of the load
                                 Q, so that


                                 where BZ = .B£)sin(/> = y4Dcos(/>sin</> and r = AD sin a. Thus




                                 where/' is the virtual coefficient of friction defined previously, and so






      4.10. Drives utilizing     In higher pairs of elements there is incomplete restraint of motion.
      friction force             Therefore, force closure is necessary if the motion of one element relative to
                                 the other is to be completely constrained. In higher pairing, friction may be
                                 a necessary counterpart of the closing force as in the case of two friction
                                 wheels (Fig. 4.32). Here, the force P not only holds the cylinders in contact,
                                 but must be sufficient to prevent relative sliding between the circular
                                 elements if closure is to be complete.
                                   Now, consider the friction drive between two pulleys connected by a belt,
                                 Fig. 4.33, then for the pair of elements represented by the driven pulley and
      Figure 4.32                the belt (case (b) in Fig. 4.33), the belt behaves as a rigid body in tension
                                 only. If the force T 1 were reversed, or the belt speed V were to fall
                                 momentarily below ra, this rigidity would be lost. Hence, force closure is
                                 incomplete, and the pulley is not completely restrained since a degree of
                                 freedom may be introduced. A pulley and that portion of the belt in contact
                                 with it, together constitute an incompletely constrained higher pair which is
                                 kinematically equivalent to a lower pair of elements.
                                   Assuming that the pulleys are free to rotate about fixed axes, complete
                                 kinematic closure is obtained when an endless flexible belt is stretched
                                 tightly over the two pulleys. The effects of elasticity are for a moment
                                 neglected, so that the belt behaves as a rigid body on the straight portions
                                 and the motion can then be reversed. This combination of two incomplete
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