Page 105 - Materials Chemistry, Second Edition
P. 105

88        Practical Design Calculations for Groundwater and Soil Remediation



             T  =  aquifer transmissivity (in gpd/ft or m /day)
                                                    2
             t  =  time since pumping started (in days)
             The infinite-series term in Equation (3.15) (the terms inside the square
           bracket) is often called the well function and designated as W(u). Tabulated
           values of  W(u) as a function of  u can be found in groundwater hydrol-
           ogy books. (The well function tables have become obsolete because of the
           convenience of hand calculators and personal computers.) A type-curve
           approach is often developed to match the time and drawdown data to the
           curve of W(u) versus 1/u. From the match points, the transmissivity and
           storativity can be determined. There are computer programs commercially
           available for Theis curve matching. This subsection will provide one exam-
           ple of using the Theis equation, but no examples for the curve matching
           will be given.



           Example 3.13:   Estimate Unsteady-State Drawdown of a
                         Confined Aquifer Using the Theis Equation
           A pumping well is installed in a confined aquifer. Use the following infor-
           mation to estimate the drawdown at a distance 20 ft away from the well after
           one day of pumping:

              •  Aquifer thickness = 30.0 ft
              •  Groundwater extraction rate = 20 gpm
              •  Aquifer hydraulic conductivity = 400 gpd/ft 2
              •  Aquifer storativity = 0.005



              Solution:
               (a)  T = Kb = (400)(30) = 12,000 gpd/ft
               (b)  Inserting the data into Equation (3.16), we obtain
                            2
                                          2
                       1.87 rS    1.87(20ft) (0.005)
                    u =       =                    = 3.12 10×  − 4
                         Tt     (12,000 gpd/ft)(1 day)
               (c)  Substitute the value of u in the well function to obtain its value:
                                                                      −
                                                             (3.12 ×  10 )
                                                                      42
                                             −
                                                          −
                                              4
                                                          4
                                                +
                                  −
                    Wu() = − 0.5772 ln(3.12 × 10 )(3.12 × 10 )−  22!
                          
                                                                   ⋅
                          
                                                  −
                                    −
                                     43
                                                  44
                            (3.12 ×  10 )  (3.12 ×  10 )  
                          +             −            +  
                                 ⋅
                                              ⋅
                                33!          44!        
                         =  7.50
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