Page 181 - Materials Chemistry, Second Edition
P. 181

164       Practical Design Calculations for Groundwater and Soil Remediation



             If no pilot tests are conducted, an estimate could be made based on previous
           experiences. The R  values ranging from 30 ft (9 m) to 100 ft (30 m) are reported
                            I
           in the literature, and typical pressures in the extraction wells range from 0.90
           to 0.95 atm [3]. Shallower wells, less permeable subsurface, and lower applied
           vacuum in the extraction well generally correspond to smaller R  values.
                                                                   I

           Example 5.7:   Determine the Radius of Influence of a Soil-Venting
                        Well by Using the Pressure Drawdown Data (Pressure
                        Data Are Given in the Atmospheric Unit)
           Determine the radius of influence of a soil-venting well using the following
           information:

              •  Pressure at the extraction well = 0.9 atm
              •  Pressure at a monitoring well 30 ft away from the venting well = 0.98
                atm
              •  Diameter of the venting well = 4 in.

              Solution:
               (a)  Let us define the R  as the location where P is equal to the atmo-
                                    I
                   spheric pressure. The R  can be found by using Equation (5.3) as:
                                        I
                                                     rR )
                                   2
                                 P r − P w ( P RI − P w)  ln(/ w
                                            2
                                                2
                                       2
                                        =
                                                    RR )
                                                     I
                                                  ln(/ w
                                                    ln[30/(2/12)]
                                             2
                                       2
                                                  2
                                2
                           (0.98) − (0.9) = (1.0 −  0.9 )
                                                    ln[/(2/12)]
                                                      R I
                   R  = 118 ft
                     I
               (b)  For comparison, let us now define the R  as the location where
                                                        I
                   the drawdown is equal to 1% of the vacuum in the extraction
                   well:
                   The vacuum in the extraction well = 1 − 0.9 = 0.1 atm
                   Thus, P  = 1 − (0.1)(1%) = 0.999 atm
                          RI
                                                     ln[30/(2/12)]
                                                   2
                               2
                          (0.98) − (0.9) = (0.999 − 0.9 )
                                              2
                                      2
                                                       R I
                                                     ln[/(2/12)]
                   R  = 110 ft
                     I
              Discussion:
              The R  value from part (b), 110 ft, is about 7% smaller than that from
                   I
                part (a).
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