Page 282 - Materials Chemistry, Second Edition
P. 282

Groundwater Remediation                                          265



             In situ chemical oxidation is considered as one of the remedial alterna-
           tives. Determine the stoichiometric amount of potassium permanganate that
           needs to be delivered to the zone. What would be the amount if sodium
           persulfate is used?

              Solution:
              Basis: 1 m  of aquifer
                       3
               (a)  Determine log K  from Table 2.5:
                                  ow
                       log K  = 2.6
                           ow
                   Use Equation (2.28) to find K :
                                             oc
                       K  = 0.63K  = 0.63(10 ) = (0.63)(398) = 251
                                          2.6
                        oc
                                ow
                   Use Equation (2.26) to find K :
                                             p
                       K  = f K  = (0.02)(251) = 5.02 L/kg
                           oc
                        p
                              oc
                   Use Equation (2.25) to find PCE concentration adsorbed onto the
                       solid:
                       S = K C = (5.02 L/kg)(400 mg/L) = 2,006 mg/kg
                           p
               (b)  Determine the total mass of PCE present in the aquifer (per m ):
                                                                          3
                   Mass of the aquifer materials = (1 m )(1,600 kg/m ) = 1,600 kg
                                                               3
                                                   3
                   Mass of PCE adsorbed on the solid surface = (S)(M )
                                                                s
                       = (2,006 mg/kg)(1,600 kg) = 3,210,000 mg = 3,210 g
                   Pore volume of the aquifer = V × ϕ
                       = (1 m )(35%) = 0.35 m  = 350 L
                                          3
                            3
                   Mass of PCE dissolved in the groundwater = (C)(V)
                                                                l
                       = (400 mg/L)(350 L) = 140,000 mg = 140 g
                   Total mass of PCE in the aquifer = dissolved + adsorbed
                       = 140 + 3,210 = 3,350 g of PCE/m  of aquifer
                                                   3
               (c)  MW of PCE (C Cl ) = (12)(2) + (35.5)(4) = 166
                                   4
                                2
                   MW of potassium permanganate (KMnO ) = (39)(1) + (55)(1) +
                                                         4
                       (16)(4) = 158
                   Moles of PCE = 3,350 g/m  of aquifer
                                          3
                       = (3,350 g ÷ 166 g/mole)/m  of aquifer
                                              3
                       = 20.2 moles of PCE/m  of aquifer
                                           3
                   As shown in Equation (5.42), the stoichiometric requirement to
                       oxidize PCE is 4/3 mole permanganate per mole of PCE.
                   Stoichiometric amount of KMnO  needed per m  of aquifer
                                                              3
                                                 4
                       = (4 moles of KMnO /3 moles of PCE) × (20.2 moles of PCE/
                                         4
                          m  of aquifer)
                            3
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