Page 284 - Materials Chemistry, Second Edition
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Groundwater Remediation                                          267



           where C is the COC concentration in groundwater, V is the reactor volume,
           Q is the groundwater flow rate, k is the rate constant, and τ is the hydraulic
           retention time.
             Another design approach is to use electrical energy per order of destruction
           (EE/O) to scale up an AOP reactor. An EE/O of 5 kWh/1,000 gal/order of COC
           destruction means that it will take 5 kWh of energy to reduce the COC concen-
           tration from 1 ppm to 0.1 ppm in 1,000 gal of groundwater. It will take another 5
           kWh of energy to reduce the concentration from 0.1 ppm to 0.01 ppm. It should
           be noted that the value of EE/O is specific to the groundwater and COCs treated.


           Example 6.22:  Sizing the Reactor for an Advanced Oxidation Process
           UV/ozone treatment is selected to remove trichloroethylene (TCE) from an
           extracted groundwater stream (TCE concentration = 400 ppb). A pilot study
           was conducted and found that, with a hydraulic retention of 2 min, the sys-
           tem could reduce TCE concentration from 400 ppb to 16 ppb. However, the
           discharge limit for TCE is 3.2 ppb. Assuming the reactors are of ideal plug-
           flow type and the reaction is first-order, how many reactors would you rec-
           ommend to use?

              Solution:
               (a)  Use Equation (6.39) to determine the reaction rate constant:
                                                16
                               C out
                                   = exp[ − τ=k()]  = exp[ − k2]
                               C in            400
                   So, k = 1.61/min

               (b)  Use Equation (6.39) to determine the required retention time to
                   reduce the TCE concentration below the discharge limit:
                                              3.2
                                                           τ
                             C out
                                 = exp[ − τ=     = exp[ −1.61()]
                                       k()]
                             C in            400
                   τ = 3.0 min. Thus, it requires two reactors.
               (c)  Use Equation (6.39) to determine the final effluent TCE concen-
                   tration (τ = 4 min because two reactors were used):

                             C out           C out
                                       k
                                 = exp[ − τ=()]  = exp[ −1.61(4)]
                             C in            400
                   C  = 0.64 ppb
                     out
              Discussion:
                1.  For PFRs, the final concentration from two identical reactors in
                   series is the same as that from two identical reactors in parallel.
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