Page 31 - Materials Chemistry, Second Edition
P. 31

14        Practical Design Calculations for Groundwater and Soil Remediation



               (c)  Vapor concentration in ppmV:
                   MW of methylene chloride [CH Cl ]  = (12) + (1)(2) + (35.5)(2)
                                                  2
                                               2
                                                    = 85 g/mole
                   At T = 20°C and P = 1 atm,
                       1 ppmV of methylene chloride  = (85/24.05) mg/m 3
                                                  = 3.53 mg/m 3

                   Vapor concentration in vol/vol =  7,417  mg/m  ÷ [3.53 (mg/m )/
                                                                          3
                                                           3
                                                 ppmV] = 2,100 ppmV
           	    ∴  It would exceed the PEL and the STEL.
              Discussion:
                1.  Specific gravity is the ratio of the density of a substance to the
                   density of a reference substance, most commonly water at 4°C (=
                   1 g/cm  = 9.807 kN/m ).
                          3
                                       3
                2.  STEL is based on a sampling period of 15 min.
                3.  This calculation illustrates that a relatively small amount of COC
                   emission could yield unhealthy air quality.
           Example 2.5:   Mass and Concentration Relationship

           A boy went  into  a site and played with dirt impacted with ethyl benzene
           (C H C H ). During his stay at the site, he inhaled 2 m  of air containing 10
                                                            3
              6
                5
                    5
                  2
           ppbV of ethyl benzene and ingested a mouthful (≈1 cm ) of soil containing 5
                                                            3
           ppmethyl benzene. Which system (ingestion or inhalation) is exposed to more

           ethyl benzene? Assume the total bulk density of soil is equal to 1.8 g/cm .
                                                                          3
              Solution:
               (a)  Ethyl benzene inhaled
                   MW of ethyl benzene (C H C H )  = (12)(8) + (1)(10) = 106 g/mole
                                         6
                                           5
                                             2
                                                5
                   At T = 20°C and P = 1 atm,
                   10 ppbV of ethyl benzene  = (10 × 10 )(106/24.05) mg/m 3
                                                  −3
                                          = 0.0441 mg/m 3
                   Mass of ethyl benzene inhaled
                       = (air volume)(vapor concentration)
                       = (2 m )(0.0441 mg/m ) = 0.0882 mg

                                         3
                            3
               (b)  Ethyl benzene ingested
                   	   =  [(soil volume)(total bulk density)](COC concentration in soil)
                   	   = [(1 cm )(1.8 g/cm )(1 kg/1,000 g)](5 mg/kg)
                                       3
                              3
                   	   = (1.8 × 10 )(5) = 0.0090 mg
                               −3
           	    ∴  The inhalation system is exposed to more ethyl benzene.
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