Page 36 - Materials Chemistry, Second Edition
P. 36

Site Assessment and Remedial Investigation                        19



              Step 3:  Determine the number and volumes of the USTs removed.
              Step 4:   Subtract the total volume of the USTs from the volume of the
                    tank pit.
              Step 5:  Multiply the value from Step 4 with a soil fluffy factor.

             Information needed for this type of calculation

              •  Dimensions of the tank pit (from field measurements)
              •  Number and volumes of the USTs removed (from drawings or
                field observation)
              •  Bulk density of soil (from measurement or estimate)
              •  Soil fluffy factor (from estimate)



           Example 2.9:   Determine the Mass and Volume of
                        Soil Excavated from a Tank Pit
           Two 5,000-gallon USTs and one 6,000-gallon UST were removed. The excava-
           tion resulted in a tank pit of 50′ × 24′ × 18′. The excavated soil was stockpiled
           on site. The total bulk density of soil in situ (before excavation) is 1.8 g/cm
                                                                              3
           and that of soil in the stockpiles is 1.5 g/cm . Estimate the volume and mass
                                                  3
           of the excavated soil.
              Solution:
              Volume of the tank pit = (50′)(24′)(18′) = 21,600 ft 3
              Total volume of the USTs = (2)(5,000) + (1)(6,000) = 16,000 gal
                	  		              	 		= (16,000 gal)(ft /7.48 gal) = 2,139 ft 3
                                                  3
              Volume of soil in the tank pit before removal
                = (volume of tank pit) − (volume of USTs)
                = 21,600 − 2,139 = 19,461 ft 3

              Volume of soil excavated (in the stockpiles)
                = (volume of soil in the tank pit) × (fluffy factor)
                = (19,461)(1.2) = 23,353 ft 3
                = (23,353 ft )(yd /27 ft ) = 865 yd 3
                                   3
                          3
                              3
              Mass of soil excavated =  (volume of the soil in the tank pit)(total bulk
                                    density of soil in situ)
                	  		             =  (volume of the soil in the stockpile)(total bulk
                                    density of soil in the stockpile)
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