Page 204 - A Course in Linear Algebra with Applications
P. 204

188               Chapter  Six:  Linear  Transformations

            and

                  TiT 2 (/)  =  T 1(T 2(f))=T 1(xf"  -  2/')
                                        =  ( * / " - 2 / ' ) ' - ( * / " - 2 / ' ) ,


            which  reduces  to  TiT 2 (/)  =  2/'  -  (x  +  1)/"  +  xf^\  after
            evaluation  of the  derivatives.

                 At  this  point  one  can  sit  down  and  check  that  those
            properties  of  matrices  listed  in  1.2.1  which  relate  to  sums,
            scalar  multiples  and  products  are  also  valid  for  linear  oper-
            ators.  Thus   there  is  a  similarity  between  the  set  of  linear
            operators  L(V)  and  M n(F),  the  set  o f n x n  matrices  over  F
            where  n  =  dim(V).   This  similarity  should  come  as  no  sur-
            prise  since  the  action  of  a  linear  operator  can  be  represented
            by  multiplication  by  a suitable  matrix.
                 The  relation  between  L(V)  and  M n(F)  can be  formalized
            by  defining  a  new  type  of  algebraic  structure.  This  involves
            the  concept  of  a  ring,  which  was  was  described  in  1.3,  and
            that  of  a  vector  space.
                 An  algebra A  over  a  field  F  is  a  set  which  is  simultane-
            ously  a  ring  with  identity  and  a  vector  space  over  F,  with
            the  same  rule  of addition  and  zero element,  which  satisfies  the
            additional  axiom

                                 c(xy)  =  (cx)y  =  x(cy)

            for  all  x  and  y  in  A  and  all  c  in the  field  F.  Notice  that  this
            axiom   holds  for  the  vector  space  M n(F)  because  of  property
             (j)  in  1.2.1.  Hence  M n{F)  is  an  algebra  over  F.  Now  the
            additional  axiom  is  also  valid  in  L(V),  that  is,

                             c(T lT 2)  =  (cT 1)T 2  =  T l(cT 2).


            This  is  true  because  each  of  the  three  linear  operators  men-
            tioned  sends  the  vector  v  to  c(Ti(T 2 (v))).  It  follows  that
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