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9.4:  Jordan  Normal  Form               363


        respectively,  where  m;  is  the  sum  of  the  numbers  of  columns
        in  Jordan  blocks  with  eigenvalue  ci  and  ki  is  the  number  of
        columns  in  the  largest  such  Jordan  block.

        Example     9.4.9
        Find  the  minimum   polynomial  of the  matrix



                              A  =




             The  Jordan  form  of  A  is

                                /  2     1    I   0  \
                                   0     2     1 0
                          N
                                        —     I
                                V  0     0     1 2 /

        by  Example  9.4.7.  Here  2 is the  only  eigenvalue  and  there  are
        two Jordan  blocks, with  2 and  1 columns.  The minimum   poly-
                                          2
        nomial  of  A  is therefore  (x  — 2) .  Of  course the  characteristic
                               3
        polynomial   is  (2 — x) ,
        Application    of  Jordan   form  to  differential  equations
             In  8.3  we studied  systems  of  first  order  linear  differential
        equations  for  functions  yi,  y.2,...,  y n  of  a  variable  x.  Such  a
        system  takes  the  matrix  form


                                   Y'  =  AY.

        Here  Y  is the  column  of  functions  y\,.  .., y n  and  A  is  an  n  x
        n  matrix  with  constant  coefficients.  Since  any  such  matrix
        A  is  similar  to  a  triangular  matrix  (by  8.1.8),  it  is  possible
        to  change  to  a  system  of  linear  differential  equations  for  a
        new  set  of  functions  which  has  a triangular  coefficient  matrix.
        This  new  system   can  then  be  solved  by  back  substitution,
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