Page 163 - Adsorption Technology & Design, Elsevier (1998)
P. 163

Design procedures  151


            (6.22))  and  a  finite  mass  transfer  rate  will  prevent  the  formation  of  the
            limiting condition which is a compressive shock transition (step change) that
            travels through  the bed with a velocity determined by a mass balance over
            the MTZ:

               dz         u
              --  =                                                     (6.25)
               dt

                    1 + pp       AC

            A  perfect shock front can only be attained if there are no dispersive effects,
            i.e.  if  there  is  no  axial  dispersion,  and  if  there  are  no  mass  transfer
            resistances to the adsorption process. Such a situation is most unlikely, since
            even if the mass transfer resistances were extremely low, the axial dispersion
            effects  would  become  significant  as  the  step  change  or  shock  were
            approached and the shape of the MTZ would tend to become fixed.
              There  can  be  no  change  of  shape  in  the  MTZ  if the  isotherm  is  linear
            (equation  (6.26))  because  in  this case  all  the  terms  on  the  right-hand  side
            of equation  (6.24)  would  be  independent  of the  fluid phase  concentration
            C.

              q* = Kc                                                   (6.26)
            The time taken for a point of given fluid concentration to move through the
            bed  can  be  obtained  from  equation  (6.24).  Consider  the  case  of  a  linear
            isotherm and an initially clean bed. Assume that breakthrough occurs when
            the  fluid  phase  concentration  is just  about  to  increase  beyond  zero.  By
            setting dq*/dc = K  in equation  (6.24), the time to breakthrough for a given
            bed  length can  be obtained  or, vice versa, a bed length for a given time to
            breakthrough can be obtained:

              t=  Lu-~l +pp  (~~-~)K]                                   (6.27)


            In the case of a Langmuir isotherm (see Section 3.3.1):

                    bqmc
              q* =                                                      (6.28)
                    1 +bc
            the slope of the isotherm is as follows:

              dq*      bqm
              dc     (1  +  bc) 2                                       (6.29)
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