Page 301 - Advanced Design Examples of Seismic Retrofit of Structures
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290   Advanced Design Examples of Seismic Retrofit of Structures


                                            αωL 2
                                        Δ s ¼                           (5.3)
                                            8AG
            where:
               ω ¼uniform distributed load;
               E ¼Young’s modulus of material;
               I ¼moment of inertia of the section;
               α ¼form coefficient;
               A ¼diaphragm’s cross-sectional area; and
               G ¼shear modulus of the section.
               The diaphragms should be designed for the inertial force F pi based on Eq.
            (5.4).
                                         X  n
                                              F j
                                            j¼i
                                    F pi ¼ X n     W i                  (5.4)
                                              W j
                                            j¼i
            where:
               F j ¼lateral force acting on the jth story;
               W j ¼weight of the jth story; and
               W i ¼weight of the jth story.
               For the main building we have:

                                ð
                           t ¼ 11 cmÞ
                           H ¼ 1510 cmÞ
                                   ð
                           L ¼ 3130 cmÞ
                                   ð
                                  ð
                           h ¼ 900 cmÞ
                           l ¼ 2160 cmÞ
                                  ð
                                                        2
                           A x ¼ t L ¼ 11 3130 ¼ 34430 cmð  Þ
                                                      2
                           A y ¼ t h ¼ 11 900 ¼ 9900 cmð  Þ
                           Δ Diaphragm XðÞ ¼ 11:06 cmð  Þ
                           Δ Diaphragm YðÞ ¼ 4:04 cmð  Þ

                                       kg
                           G ¼ 12512:5
                                       cm 2
                                        kg

                                     6
                           E ¼ 2:1 10
                                       cm 2
                           F 1PxðÞ ¼ 1549:68 TðÞ
                           F 1PyðÞ ¼ 1224:82 TðÞ
                                  1549:68 10 3          kg   f
                           F 1PXðÞ ¼          ¼ 1026:27
                                      1510              cm
                                  1224:82 10 3         kg   f
                           F 1PYðÞ ¼          ¼ 391:31
                                      3130             cm
                               11 3130 3                   4
                           I X ¼        ¼ 28108938916:67 cm
                                  12
                               11 900 3               4
                           I Y ¼       ¼ 668250000 cm
                                  12
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