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682    CHAPTER 19  Complex Numbers and Functions

                                    The theorem states that the Cauchy-Riemann equations are necessary for f = u + iv to
                                 be differentiable at a point. If u, v, and their first partial derivatives are continuous, then the
                                 Cauchy-Riemann equations are also sufficient for f to be differentiable.
                                    Using the Cauchy-Riemann equations, we can establish the following results.


                           THEOREM 19.5

                                 Let f be differentiable on an open disk D.Let f = u + iv, and suppose that u and v are con-
                                 tinuous with continuous first and second partial derivatives, and satisfy the Cauchy-Riemann
                                 equations on D. Then
                                    1. If f (z) = 0on D, then f is a constant function on D.

                                    2. If | f (z)| is constant on D,sois f (z).

                                 Proof  Conclusion (1) is easy to prove. For each z in D,
                                                                        ∂u   ∂v

                                                              f (z) = 0 =  + i
                                                                        ∂x   ∂x
                                 implies that ∂u/∂x = ∂v/∂x = 0on D. By the Cauchy-Riemann equations, ∂u/∂y = ∂v/∂y = 0
                                 on D also, so u and v are constant functions and therefore so is f .
                                    Conclusion (2) is more involved. Suppose | f (z)|= k for all z in D. Then
                                                                       2
                                                                                2
                                                              2
                                                         | f (z)| = u(x, y) + v(x, y) = k  2            (19.2)
                                 for (x, y) in D.If k = 0, then f (z) = 0 for all z in D.If k  = 0, differentiate equation (19.2) with
                                 respect to x to get
                                                                  ∂u    ∂v
                                                                u   + v   = 0                           (19.3)
                                                                  ∂x    ∂x
                                 and with respect to y to get
                                                                 ∂u    ∂v
                                                                u   + v   = 0.                          (19.4)
                                                                  ∂y   ∂y
                                 Use the Cauchy-Riemann equations to write equations (19.3) and (19.4) as
                                                                  ∂u    ∂u
                                                                u   − v   = 0                           (19.5)
                                                                  ∂x    ∂y
                                 and
                                                                 ∂u    ∂u
                                                                u   + v   = 0.                          (19.6)
                                                                 ∂y    ∂x
                                 Multiply equation (19.5) by u and equation (19.6) by v and add the resulting equations to get
                                                                    ∂u    2  ∂u
                                                                   2
                                                               2
                                                             (u + v )  = k    = 0.
                                                                    ∂x     ∂x
                                 Therefore, ∂u/∂x = 0on D, and by the Cauchy-Riemann equations, ∂v/∂y = 0 also. A similar
                                 manipulation shows that ∂u/∂y = ∂v/∂x = 0, so u(x, y) and v(x, y) are constant, hence f (z) is
                                 constant on D.

                                    There is an intimate connection between differentiable complex functions and harmonic
                                 functions. Recall that a real-valued function u(x, y) of two real variables is harmonic on a set of
                                 points in the x, y-plane if u satisfies Laplace’s equation




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