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19.3 The Exponential and Trigonometric Functions 687
where
1 y −y 1 y −y
cosh(y) = (e + e ) and sinh(y) = (e − e ).
2 2
To verify these, write
1 iz −iz
cos(z) = e + e
2
1 i(x+iy) −i(x+iy)
= e + e
2
1 ix −y −ix y
= e e + e e
2
1 −y y
= e (cos(x) + i sin(x)) + e (cos(x) − i sin(x))
2
1 i
y
= cos(x) e + e −y + sin(x) e −y − e y
2 2
= cos(x)cosh(y) − i sin(x)sinh(y).
Similarly,
sin(z) = sin(x)cosh(y) + i cos(x)sinh(y).
If z = x is real, then y =0, the complex sine agrees with the real sine, and the complex cosine
agrees with the real cosine. In this sense, sin(z) and cos(z) are extensions of sin(x) and cos(x)
to the complex plane.
A multiplication shows that, for all z,
2
2
cos (z) + sin (z) = 1,
as we should expect. Other identities for the real sine and cosine functions extend readily to their
complex counterparts, although their derivations are very much simplified in the complex case
because exponential functions are easy to compute with. For example, suppose we want to show
that sin(2z) = 2sin(z)cos(z). Compute
1 iz −iz iz −iz
2sin(z)cos(z) = e − e e + e
2i
1 2iz −2iz
= e − e = sin(2z).
2i
From the Cauchy-Riemann equations, cos(z) and sin(z) are differentiable for all z. Further-
more, using equations (19.1),
d ∂u ∂v
cos(z) = + i
dz ∂x ∂y
=−sin(x)cosh(y) − i cos(x)sinh(y) =−sin(z),
and similarly,
d
sin(z) = cos(z).
dz
The complex sine and cosine functions exhibit some properties that are not seen in the real
case. For example, the real sine and cosine functions are bounded: |cos(x)|≤ 1 and |sin(x)|≤ 1
for all real x. But the complex sine and cosine are not bounded functions in the complex plane.
For real y,
1
y
cos(iy) = (e −y + e ),
2
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