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824    Answers to Selected Problems

                      5. T is linear and
                                                           ⎛                ⎞
                                                             1  0  0   −1  0
                                                       A T = ⎝ 0  1  −1  0  0 ⎠ .
                                                             0  0  0    1  1

                        T is onto but not one-to-one; A T has rank 3.
                      7. Not linear because of the sin(xy) term.
                      9. T is not linear (the image of a sum of two vectors has last component 2).

                     CHAPTER EIGHT DETERMINANTS
                     Section 8.1 Definition of the Determinant
                              n
                      1. |B|= α |A|
                                   t
                                         n
                                n
                      3. |A|= (−1) |A |= (−1) |A|.
                                n
                        Since (−1) =−1if n is odd, then |A|=−|A|,so |A|= 0.
                     Section 8.2 Evaluation of Determinants I
                      1. −22   3. −14   5. −2247   7. −122
                      9. 72
                     Section 8.3 Evaluation of Determinants II
                      1. 32   3. 3   5. −773   7. −152
                      9. 1693
                     11.

                                                       1  α  α 2     1  α   α 2
                                                             2
                                                                               2
                                                                           2

                                                       1  β  β    = 0  β − α  β − α

                                                                           2
                                                                               2
                                                             2

                                                      1  γ  γ         0  γ − α  γ − α

                                                          1  α  α  2
                                                                                   1  β + α
                                           = (β − α)(γ − α) 0  1  β + α    = (β − α)(γ − α)

                                                                                   1

                                                         0  1  γ + α                 γ + α,
                        leading to the value β − α)(γ − α)(γ − β).
                     Section 8.4 A Determinant Formula for A −1
                         1     6  1
                      1.
                         13 −1  2

                         1 −4  1
                      3.
                         5  1  1
                           ⎛            ⎞
                             5    3   1
                         1
                      5.   ⎝ −8  −24  24 ⎠
                         32  −2  −14  6
                           ⎛            ⎞
                            −1   25  −21
                         1
                      7.   ⎝ −8  −3   6 ⎠
                         29  −1  −4   8
                              210   −42   42     0
                            ⎛                      ⎞
                         1 ⎜ 899   −124   223
                      9.                       −135⎟
                         378  ⎝  275  −64  109  −27  ⎠
                             −601   122  −131    81
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                                   October 14, 2010  17:50  THM/NEIL    Page-824        27410_25_Ans_p801-866
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