Page 110 - Advanced Linear Algebra
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94    Advanced Linear Algebra




            The following theorem demonstrates one way in which the  expression  =°:
            behaves like a fraction.



                        (
            Theorem 3.8 The third isomorphism theorem )  Let   be a vector space and
                                                        =
                                               =
            suppose that :‹ ; ‹ =   are subspaces of  . Then
                                        =°:    =
                                             š
                                        ;°:    ;
            Proof. Let             be defined by  ²# b :³ ~ # b ;  . We leave it to the
                                               ¢ = °: ¦ = °;
            reader to show that   is a well-defined surjective linear transformation whose

            kernel is ;°: . The rest follows from the first isomorphism theorem.…
            The following theorem demonstrates one way in which the  expression  =°:
            does not behave like a fraction.
            Theorem 3.9 Let   be a vector space and let   be a subspace of  . Suppose

                                                   :
                           =
                                                                   =
                                                   . Then
            that =~ = l =       and : ~ : l :       with : ‹ =
                                 =    =  l  =    =    =
                                    ~         š    ^
                                  :   :  l  :    :    :

            Proof. Let  = ¦ ²=°:³  ^¢  =°:³  be defined by
                                        ²



                                ²# b# ³ ~ ²# b: Á # b: ³






                                                         is direct. We leave it to
            This map is well-defined, since the sum =~ = l =
            the reader to show that   is a surjective linear transformation, whose kernel is

            :l :      . The rest follows from the first isomorphism theorem.…
            Linear Functionals
                                                     (
            Linear transformations from   to the base field    thought of as a vector space
                                                   -
                                   =
                    )
            over itself  are extremely important.
            Definition Let  =   be a vector space over  -  . A linear transformation
              ²= Á -³ whose values lie in the base field   is called a linear functional
                                                   -
               B
            (or simply functional ) on  .  (Some authors use the term linear function  ) .  The
                                  =
            vector space of all linear functionals on   is denoted by  =  *  and is called the
                                              =
            algebraic dual space of  .…
                                =
            The adjective algebraic  is needed here, since there is another type of dual space
            that is defined on general normed vector spaces,  where  continuity  of  linear
            transformations makes sense. We will discuss the  so-called  continuous dual
            space briefly in Chapter 13. However, until then, the term “dual space”  will
            refer to the algebraic dual space.
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