Page 508 - Advanced Linear Algebra
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492    Advanced Linear Algebra



            It is clear that each Sheffer sequence uniquely determines a Sheffer operator and
            vice versa. Hence, knowing the Sheffer operator of a sequence is equivalent to
            knowing the sequence.
            Continuous Operators on the Umbral Algebra

                                                 ;
            It  is  clearly  desirable  that a linear operator   on the umbral algebra  <   pass
            under infinite sums, that is, that
                                  B            B
                               ;4      ²!³ ~        5     ;´ ²!³µ       (19.6 )


                                   ~           ~
            whenever the sum on the left is defined, which is precisely when  ²  ²!³³ ¦ B

            as   ¦ B . Not all operators on  <  have  this property, which leads to the
            following definition.

            Definition A linear operator   on the umbral algebra   is  continuous  if it
                                                           <
                                     ;
            satisfies ²19.6) .…
            The term continuous can be justified by defining a topology on  . However,
                                                                  <
            since no additional topological concepts will be needed, we will not do so here.
                              (
                                  )
            Note that in order for  19.6  to make sense, we must have  ²;´  ²!³µ³ ¦ B . It

            turns out that this condition is also sufficient.
            Theorem 19.15 A linear operator   on   is continuous if and only if
                                       ;
                                            <
                                 ²  ³ ¦ B ¬  ²;²  ³³ ¦ B                (19.7 )


                                                    )
                                                (
            Proof. The necessity is clear. Suppose that  19.7  holds and that  ²  ³ ¦ B .

            For any  ‚  , we have
                      B
                                                      L ²!³ %
                                    L  ²!³ %
                  L  ;        c       M  ~ ;    c           M       b ;      c       M    ²!³ %  (19.8 )
                      ~                 ~                 €
            Since
                                      8          ²  !     ³  9  ¦  B
                                       €
            (19.7 ) implies that we may choose   large enough that

                                    ;         ²!³ €
                                    4
                                                5

                                        €
            and
                                  ²;´  ²!³µ³ €   for    €
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