Page 62 - Advanced Linear Algebra
P. 62

46    Advanced Linear Algebra




                                           and
                       # ~     bÄb              # ~   ! b Äb  !




            where the  's are distinct, the  's are distinct and all coefficients are nonzero,


                                     !
            then  ~   and after a reindexing of the   !    's if necessary, we have   ~     and

                  for all     ~  ÁÃÁ .  Note that this is  stronger  than  saying  that
                                     (
              ~ !
               ~   !     .)…

            We may characterize linear independence as follows.
            Theorem 1.6 Let : £ ¸ ¹  be a nonempty set of vectors in  . The following are
                                                            =
            equivalent:
             )
            1   :  is linearly independent.
             )
            2   Every nonzero vector  #  span²:³  is an essentially unique linear
               combination of the vectors in  .
                                       :
            3   No vector in   is a linear combination of other vectors in  .
             )
                          :
                                                              :
            Proof. Suppose that 1  holds and that
                             )
                           £ # ~     bÄb    ~   ! bÄb  !




            where the  's are distinct, the  's are distinct and the coefficients are nonzero.


                                     !
            By subtracting and grouping  's and  's that are equal, we can write

                                         !

                              ~ ²  c  ³  bÄb²  c   ³





                              b          b   b Äb
                                      b

                              c     !    b   c Äc  !
                                     b
                  )
            and so 1  implies that  ~ ~    and   ~    "     "   and   ~ !   "     "   for all   ~ Á Ã Á   .
            Thus, 1  implies 2 .
                          )
                  )
            If 2) holds and  :  can be written as

                                     ~     bÄb


            where   :  are different from  , then we may collect like terms on the right

            and then remove all terms with   coefficient. The resulting expression violates

            2). Hence, 2) implies 3). If 3) holds and
                                       bÄb    ~


                                      £     , then  €         and we may write
            where the  's are distinct and

                                  ~ c   ²    bÄb    ³






                         )
            which violates 3 .…
            The following key theorem relates the notions  of  spanning  set  and  linear
            independence.
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