Page 78 - Advanced Linear Algebra
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62    Advanced Linear Algebra



            Isomorphisms

            Definition  A  bijective linear transformation   ¢= ¦ >   is called an
            isomorphism from   to  >  . When an isomorphism from   to  >   exists, we say
                            =
                                                          =
            that   and  >   are isomorphic  and write  =  š  >  .…
               =
                                                         8
            Example 2.2 Let dim²= ³ ~   . For any ordered basis   of  , the coordinate
                                                              =
            map    8 ¢= ¦ -      that  sends each vector  #  =   to its coordinate matrix
            ´#µ  -  is an isomorphism. Hence, any   -dimensional vector space over   is

                                                                         -
              8
            isomorphic to -    .…
            Isomorphic vector spaces share many properties, as the next theorem shows. If
               B ²= Á > ³ and  : ‹ =  we write
                                            :~ ¸   “    :¹


            Theorem 2.4 Let  ²= Á > ³  be an isomorphism. Let : ‹ =  . Then
                              B
            1   :  )   spans   if and only if  :      spans  >  .
                      =
            2   :  )   is linearly independent in   if and only if  :  =      is linearly independent in
               > .
                            =
            3   :  )   is a basis for   if and only if  :      is a basis for  >  .…
            An isomorphism can be characterized as a linear transformation  ¢= ¦ >   that
            maps a basis for   to a basis for  >  .
                         =

            Theorem 2.5 A linear transformation    B ²= Á > ³  is an isomorphism if and
            only if there is a basis   for   for which  8  =      is a basis for  >  . In this case,
                               8
            maps any basis of   to a basis of  >  .…
                           =
            The following theorem says that, up to isomorphism, there is only one vector
            space of any given dimension over a given field.
            Theorem 2.6 Let   and  >   be vector spaces over  . Then  =  š  >   if and only

                                                     -
                          =
            if dim²= ³ ~  dim²>  . ³ …
            In Example 2.2, we saw that any  -dimensional vector space is isomorphic to

            -                  ) . Now suppose that   is a set of cardinality   and let    ²  -  ) ³     be the vector
            space of all functions from   to   with finite support. We leave it to the reader
                                      -
                                  )
                                       )                     by
            to show that the functions        ²- ³   defined for all   )
                                                 %  ~ if
                                       ²%³ ~ F
                                                 %  £ if
                           )  , called the standard basis . Hence, dim  )  .
                                                                       ((

            form a basis for ²- ³                             ²²- ³ ³ ~ )
            It follows that for any cardinal number  , there is a vector space of dimension  .


                                                           )

            Also, any vector space of dimension   is isomorphic to ²- ³   .
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