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160    CHAPTER 6  Vectors and Vector Spaces

                                 having the standard unit vectors in the first row, the components of F in the second row, and the
                                 components of G in the third row. If this determinant is expanded by the first row, we get exactly
                                 F × G:


                                                                   i   j  k



                                                                  a 1  b 1  c 1


                                                                  a 2  b 2  c 2

                                                           b 1  c 1  a 1  c 1  a 1  b 1

                                                        =          i −        j +        k
                                                           b 2  c 2  a 2  c 2  a 2  b 2

                                                   = (b 1 c 2 − b 2 c 1 )i + (a 2 c 1 − a 1 c 2 )j + (a 1 b 2 − a 2 b 1 )k
                                                   = F × G.
                                    The cross product of two 3-vectors can be computed in MAPLE using the CrossProduct
                                 command, which is part of the VectorCalculus package.
                                    We will summarize some properties of the cross product.

                                    1. F × G =−G × F.
                                    2. F × G is orthogonal to both F and G. This is shown in Figure 6.14.
                                    3.   F × G  =  F    G   sin(θ) in which θ is the angle between F and G.
                                    4. If F and G are nonzero vectors, then F × G = O if and only if F and G are parallel.
                                    5. F × (G + H) = F × G + F × H.
                                    6. α(F × G) = (αF) × G = F × (αG).

                                    Property (1) of the cross product follows from the fact that interchanging two rows of a
                                 determinant changes its sign. In computing F × G, the components of F are in the second row
                                 of the determinant, and those of G in the third row. These rows are interchanged in computing
                                 G × F.
                                    For property (2), compute the dot product
                                                F · (F × G)

                                                = a 1 [b 1 c 2 − b 2 c 1 ]+ b 1 [a 2 c 1 − a 1 c 2 ]+ c 1 [a 1 b 2 − a 2 b 1 ]= 0.
                                 Therefore, F is orthogonal to F × G. Similarly, G is orthogonal to F × G.







                                                               F × G
                                                                         G



                                                                           F
                                                          FIGURE 6.14 F×G is orthogonal
                                                          to F and to G.





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