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8     CHAPTER 1 First-Order Differential Equations

                                                                       x
                                                   –1       0       1        2       3



                                                        –0.4



                                                        –0.8
                                                      y

                                                        –1.2



                                                        –1.6



                                                         –2

                                                   FIGURE 1.3 Graph of the solution of Example 1.4.

                                 Some Applications of Separable Equations

                                 Separable differential equations arise in many contexts. We will discuss three of these.


                         EXAMPLE 1.5 Estimated Time of Death
                                 A homicide victim is discovered and a lieutenant from the forensics laboratory is summoned to
                                 estimate the time of death.
                                    The strategy is to find an expression T (t) for the body’s temperature at time t, taking into
                                 account the fact that after death the body will cool by radiating heat energy into the room. T (t)
                                 can be used to estimate the last time at which the victim was alive and had a “normal” body
                                 temperature. This last time was the time of death.
                                    To find T (t), some information is needed. First, the lieutenant finds that the body is located
                                 in a room that is kept at a constant 68 Fahrenheit. For some time after death, the body will lose
                                                               ◦
                                 heat into the cooler room. Assume, for want of better information, that the victim’s temperature
                                 was 98.6 at the time of death.
                                        ◦
                                    By Newton’s law of cooling, heat energy is transferred from the body into the room at a rate
                                 proportional to the temperature difference between the room and the body. If T (t) is the body’s
                                 temperature at time t, then Newton’s law says that, for some constant of proportionality k,
                                                               dT
                                                                  = k[T (t) − 68].
                                                               dt
                                 This is a separable differential equation, since
                                                                  1
                                                                      dT = kdt.
                                                                T − 68
                                 Integrate to obtain

                                                               ln|T − 68|= kt + c.




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