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10     CHAPTER 1 First-Order Differential Equations

                                 This is an estimate, because an educated guess was made of the body’s temperature before death.
                                 It is also impossible to keep the room at exactly 68 . However, the model is robust in the sense
                                                                          ◦
                                 that small changes in the body’s normal temperature and in the constant temperature of the room
                                 yield small changes in the estimated time of death. This can be verified by trying a slightly
                                 different normal temperature for the body, say 99.3 , to see how much this changes the estimated
                                                                         ◦
                                 time of death.


                         EXAMPLE 1.6 Radioactive Decay and Carbon Dating
                                 In radioactive decay, mass is lost by its conversion to energy which is radiated away. It has
                                 been observed that at any time t the rate of change of the mass m(t) of a radioactive element
                                 is proportional to the mass itself. This means that, for some constant of proportionality k that is
                                 unique to the element,
                                                                   dm
                                                                      = km.
                                                                   dt
                                 Here k must be negative, because the mass is decreasing with time.
                                    This differential equation for m is separable. Write it as
                                                                  1
                                                                    dm = kdt.
                                                                  m
                                 A routine integration yields
                                                                 ln|m|= kt + c.

                                 Since mass is positive, |m|= m and
                                                               m(t) = e kt+c  = Ae kt

                                 in which A can be any positive number. Any radioactive element has its mass decrease according
                                 to a rule of this form, and this reveals an important characteristic of radioactive decay. Suppose
                                 at some time τ there are M grams. Look for h so that, at the later time τ + h, exactly half of this
                                 mass has radiated away. This would mean that

                                                                  M
                                                                                 kτ kh
                                                        m(τ + h) =   = Ae k(τ+h)  = Ae e .
                                                                   2
                                      kτ
                                 But Ae = M, so the last equation becomes
                                                                  M
                                                                          kh
                                                                     = Me .
                                                                   2
                                 Then
                                                                        1
                                                                    kh
                                                                    e = .
                                                                        2
                                 Take the logarithm of this equation to solve for h, obtaining
                                                                     1
                                                                1          1
                                                            h =  ln     =− ln(2).
                                                                k    2     k
                                 This is positive because k < 0.
                                    Notice that h, the time it takes for half of the mass to convert to energy, depends only
                                 on the number k, and not on the mass itself or the time at which we started measuring the
                                 loss. If we measure the mass of a radioactive element at any time (say in years), then h years
                                 later exactly half of this mass will have radiated away. This number h is called the half-life




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                                    October 14, 2010  14:9   THM/NEIL   Page-10         27410_01_ch01_p01-42
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