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270    CHAPTER 9  Eigenvalues, Diagonalization, and Special Matrices

                                    To find an eigenvector associated with the eigenvalue 1, put λ = 1 in (2) of the theorem and
                                 solve the system
                                                                 ⎛         ⎞⎛ ⎞     ⎛ ⎞
                                                                   0  1   0    x 1    0
                                                    ((1)I 3 − A)X = 0  0 −1 ⎠⎝ x 2 ⎠  = 0 ⎠ .
                                                                                    ⎝
                                                                 ⎝
                                                                   0  0   2    x 3    0
                                 This system of three equations in three unknowns has the general solution
                                                                     ⎛ ⎞
                                                                      α
                                                                     ⎝ 0 ⎠
                                                                      0
                                 and this is an eigenvector associated with 1 for any α  = 0.
                                    For eigenvectors associated with −1, put λ =−1 in (2) of the theorem and solve
                                                                    ⎛            ⎞
                                                                     −2   1    0
                                                     ((−1)I 3 − A)X =  ⎝ 0  −2  −1 ⎠ X = O.
                                                                      0   0    0
                                 This system has the general solution
                                                                   ⎛     ⎞
                                                                      β
                                                                   ⎝ 2β ⎠
                                                                     −4β
                                 and this is an eigenvector associated with −1 for any β  = 0.




                         EXAMPLE 9.4

                                 Let

                                                                     1  −2
                                                                A =          .
                                                                     2   0
                                 The characteristic polynomial is

                                                            λ   0     1  −2        λ − 1  2    2

                                                                   −           =          = λ − λ + 4,
                                                             0  λ     2   0        −2  λ
                                          p A (λ) =|λI 2 − A|=
                                 with roots
                                                                √           √
                                                             1 +  15i    1 −  15i
                                                                     and
                                                                2           2
                                 and these are the eigenvalues of A.
                                                                       √                 √
                                    For an eigenvector corresponding to (1 +  15i)/2solve (((1 +  15i)/2)I 2 − A)X = O,
                                 which is
                                                           √

                                                       1 +  15i  10       1  −2
                                                                      −           X = O.
                                                           2     01       2  0
                                 This is the system
                                                            √
                                                      ⎛                    ⎞
                                                       −1 +   15i
                                                                      2
                                                            2         √
                                                      ⎜                    ⎟  x 1    0
                                                      ⎜                    ⎟      =    .
                                                      ⎝            1 +  15i  ⎠ x 2   0
                                                           −2
                                                                      2
                                 This 2 × 2 system has general solution

                                                                       1
                                                               α      √       .
                                                                  (1 −  15i)/4
                                                                   √
                                 This is an eigenvector associated with (1 +  15i)/2 for any α  = 0.
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                                   October 14, 2010  14:49  THM/NEIL   Page-270        27410_09_ch09_p267-294
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