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356    CHAPTER 11   Vector Differential Calculus

                                 with c an arbitrary constant. Next integrate
                                                                   dy
                                                                      =−dz
                                                                   2y
                                 to get

                                                                1
                                                                 ln|y|=−z + k.
                                                                2
                                 It is convenient to express two of the variables in terms of the third. If we write x and y in terms
                                 of z we have
                                                                  1
                                                             x =     and y = ae −2z ,
                                                                z − c
                                 in which a is constant. This gives us parametric equations of the streamlines, with z as the
                                 parameter. If we want the streamline through a particular point, we must choose a and c accord-
                                 ingly. For example, suppose we want the streamline through (−1,6,2). Then z = 2 and we
                                 need
                                                                   1
                                                                               −4
                                                            −1 =      and 6 = ae .
                                                                  2 − c
                                                  4
                                 Then c = 3 and a = 6e so the streamline through (−1,6,2) has parametric equations
                                                                1
                                                           x =    , y = 6e 4−2z , z = z.
                                                              z − 3


                        SECTION 11.3        PROBLEMS



                     In each of Problems 1 through 6, find the streamlines of  4. F = cos(y)i + sin(x)j;(π/2,0,−4)
                     the vector field and also the streamline through the given
                                                                          z
                     point.                                        5. F = 2e i − cos(y)k;(3,π/4,0)
                                                                           2
                                                                                  3
                              2
                     1. F = i − y j + zk;(2,1,1)                   6. F = 3x i − yj + z k;(2,1,6)
                     2. F = i − 2j + k;(0,1,1)                     7. Construct a vector field whose streamlines are circles
                                  x
                     3. F = (1/x)i + e j − k;(2,0,4)                  about the origin.

                     11.4        The Gradient Field



                                   Let ϕ(x, y, z) be a real-valued function of three variables. In the context of vector fields, ϕ
                                   is called a scalar field.The gradient of ϕ is the vector field
                                                                  ∂ϕ   ∂ϕ    ∂ϕ
                                                             ∇ϕ =   i +   j +  k.
                                                                  ∂x   ∂y    ∂z
                                   The symbol ∇ϕ is read "del ϕ" and ∇ is called the del operator.If ϕ is a function of just
                                   (x, y), then ∇ϕ is a vector field in the plane.
                                       ∇ is also often called nabla.






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                                   October 15, 2010  16:11  THM/NEIL   Page-356        27410_11_ch11_p343-366
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