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382    CHAPTER 12  Vector Integral Calculus


                                    Conversely, suppose  F · dR is independent of path in D and let C be any closed path in
                                                      C
                                 D. Choose distinct points P 0 and P 1 on C.Let C 1 be the part of C from P 0 to P 1 and C 2 the part
                                                         C 2 . Furthermore, C 1 and −C 2 are paths in D from P 0 to P 1 ,soby

                                 from P 1 to P 0 . Then C = C 1
                                 assumption

                                                          F · dR =   F · dR =−   F · dR.
                                                        C 1       −C 2         C 2
                                 Then

                                                      0 =   F · dR +  F · dR =  F · dR.
                                                          C 1       C 2       C

                                    Thus far, we have the following implications for  F · dR over paths in some region D:
                                                                            C

                                    1. Conservative F ⇒ independence of path of  F · dR.
                                                                           C
                                    2. Independence of path in D ⇐⇒ integrals over all closed paths in D are zero.
                                    We will improve on this table of implications shortly. First, consider the problem of finding
                                 a potential function for a conservative vector field. Sometimes this can be done by integration.


                         EXAMPLE 12.11

                                 We will determine if the vector field
                                                                2
                                                                      3 2
                                                                           z
                                                                                  3
                                                              2
                                                                                         z
                                                 F(x, y, z) = 3x yz i + (x z + e )j + (2x yz + ye )k.
                                 is conservative by attempting to find a potential function.
                                    If F =∇ϕ for some ϕ, then
                                                               ∂ϕ
                                                                         2
                                                                      2
                                                                  = 3x yz ,                             (12.5)
                                                               ∂x
                                                               ∂ϕ
                                                                           z
                                                                     3 2
                                                                  = x z + e ,                           (12.6)
                                                                ∂y
                                                               ∂ϕ     3      z
                                                                  = 2x yz + ye .                        (12.7)
                                                                ∂z
                                 Choose one of these equations, say 12.5. To reverse ∂ϕ/∂x, integrate this equation with respect
                                 to x to get

                                                                    2
                                                                      2
                                                                               2
                                                                             3
                                                     ϕ(x, y, z) =  3x yz dx = x yz + α(y, z).
                                 The “constant of integration” may involve y and z because the integration reverses a partial
                                 differentiation in which y and z were held fixed. Now we know ϕ to within α(y, z). To determine
                                 α(x, y), choose one of the other equations, say 12.6, to get
                                                        ∂ϕ             ∂
                                                             3 2
                                                                          3
                                                                   z
                                                                             2
                                                          = x z + e =   (x yz + α(y, z))
                                                        ∂y            ∂y
                                                                  ∂α(y, z)
                                                             3 2
                                                          = x z +        .
                                                                     ∂y
                                 This requires that
                                                                 ∂α(y, z)  z
                                                                         = e .
                                                                    ∂y
                                 Integrate this with respect to y, holding z fixed to get
                                                              ∂α(y, z)

                                                                           z
                                                                     dy = ye + β(z),
                                                                ∂y
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                                   October 14, 2010  14:53  THM/NEIL   Page-382        27410_12_ch12_p367-424
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