Page 402 - Advanced engineering mathematics
P. 402
382 CHAPTER 12 Vector Integral Calculus
Conversely, suppose F · dR is independent of path in D and let C be any closed path in
C
D. Choose distinct points P 0 and P 1 on C.Let C 1 be the part of C from P 0 to P 1 and C 2 the part
C 2 . Furthermore, C 1 and −C 2 are paths in D from P 0 to P 1 ,soby
from P 1 to P 0 . Then C = C 1
assumption
F · dR = F · dR =− F · dR.
C 1 −C 2 C 2
Then
0 = F · dR + F · dR = F · dR.
C 1 C 2 C
Thus far, we have the following implications for F · dR over paths in some region D:
C
1. Conservative F ⇒ independence of path of F · dR.
C
2. Independence of path in D ⇐⇒ integrals over all closed paths in D are zero.
We will improve on this table of implications shortly. First, consider the problem of finding
a potential function for a conservative vector field. Sometimes this can be done by integration.
EXAMPLE 12.11
We will determine if the vector field
2
3 2
z
3
2
z
F(x, y, z) = 3x yz i + (x z + e )j + (2x yz + ye )k.
is conservative by attempting to find a potential function.
If F =∇ϕ for some ϕ, then
∂ϕ
2
2
= 3x yz , (12.5)
∂x
∂ϕ
z
3 2
= x z + e , (12.6)
∂y
∂ϕ 3 z
= 2x yz + ye . (12.7)
∂z
Choose one of these equations, say 12.5. To reverse ∂ϕ/∂x, integrate this equation with respect
to x to get
2
2
2
3
ϕ(x, y, z) = 3x yz dx = x yz + α(y, z).
The “constant of integration” may involve y and z because the integration reverses a partial
differentiation in which y and z were held fixed. Now we know ϕ to within α(y, z). To determine
α(x, y), choose one of the other equations, say 12.6, to get
∂ϕ ∂
3 2
3
z
2
= x z + e = (x yz + α(y, z))
∂y ∂y
∂α(y, z)
3 2
= x z + .
∂y
This requires that
∂α(y, z) z
= e .
∂y
Integrate this with respect to y, holding z fixed to get
∂α(y, z)
z
dy = ye + β(z),
∂y
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October 14, 2010 14:53 THM/NEIL Page-382 27410_12_ch12_p367-424