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402    CHAPTER 12  Vector Integral Calculus



                                                            F · Tds =   (∇× F) · ndσ.
                                                           C
                                 We will see this in Section 12.9 as Stokes’s theorem.



                        SECTION 12.7        PROBLEMS



                     1. Let C beasimpleclosedpathinthe x, y-plane with  2. Under the conditions of Problem 1, show that
                       interior D.Let ϕ(x, y) and ψ(x, y) be continuous with
                                                                              2
                                                                                     2
                       continuous first and second partial derivatives on C and  (ϕ∇ ψ − ψ∇ ϕ)dA
                       throughout D.Let                                   D
                                                                               ∂ϕ   ∂ψ         ∂ψ    ∂ϕ

                                                                        =    ψ   − ϕ    dx + ϕ   − ψ    dy.
                                          2
                                               2
                                         ∂ ψ  ∂ ψ                          C   ∂y    ∂y        ∂x    ∂x
                                     2
                                   ∇ ψ =     +    .
                                         ∂x  2  ∂y 2               3. Let C be a simple closed path in the x, y-plane, with
                                                                      interior D.Let ϕ be continuous with continuous first
                       Prove that
                                                                      and second partial derivatives on C and throughout D.
                                                                      Let N(x, y) be the unit outer normal to C (outer mean-

                               2
                             ϕ∇ ψ dA                                  ing pointing away from D from points on C). Prove that
                            D
                                                                                             2
                                ∂ψ      ∂ψ                                    ϕ N (x, y)ds =  ∇ ϕ(x, y)dA.
                          =   −ϕ   dx + ϕ  dy −    ∇ϕ ·∇ψ dA.                C             D
                            C   ∂y       ∂x      D
                                                                      (Recall that ϕ N is the directional derivative of ϕ in the
                                                                      direction of N.)
                     12.8        The Divergence Theorem of Gauss
                                 The discussion of the preceding section suggested a possible extension of Green’s theorem to
                                 three dimensions, yielding what is known as the divergence theorem.


                           THEOREM 12.8   The Divergence Theorem of Gauss

                                 Let   be a piecewise smooth closed surface bounding a region M of 3-space. Let   have unit
                                 outer normal n.Let F be a vector field with continuous first and second partial derivatives on
                                 and throughout M. Then


                                                             F · ndσ =    ∇· FdV.                      (12.10)

                                                                       M
                                    The theorem is named for the great nineteenth-century German mathematician and scientist
                                 Carl Friedrich Gauss, and is actually a conservation of mass equation. Recall that the diver-
                                 gence of a vector field at a point is a measure of the flow of the field away from that point.
                                 Equation (12.10) states that the flux of the vector field outward from M across   exactly bal-
                                 ances the flow of the field from each point in M. Whatever crosses the surface and leaves M must
                                 be accounted for by flow out of M (in the absence of sources or sinks in M).
                                    We will look at two computational examples to get some feeling for equation (12.10), and
                                 then consider applications.




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