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13.2 The Fourier Series of a Function  429



                               SECTION 13.1        PROBLEMS


                            1. Let                                         2. Let p(x) be a polynomial. Prove that there is no number
                                               N                             k such that p(x) = k sin(nx) on [0,π] for any positive
                                            4     1 − (−1) n
                                      S N (x) =          sin(nx).            integer n.
                                            π       n 3
                                              n=1
                                                                           3. Let p(x) be a polynomial. Prove that there is no finite
                              Construct graphs of S N (x) and x(π − x),for 0≤ x ≤π,    N
                                                                             sum     b n sin(nx) that is equal to p(x) for 0≤ x ≤π,
                              for N =2andthen N =10. This will give some sense of  n=1
                                                                             for any choice of the numbers b 1 ,··· ,b N .
                              the correctness of Fourier’s claim that this polynomial
                              could be exactly represented by the infinite series
                                            ∞
                                         4     1 − (−1) n
                                                      sin(nx)
                                         π       n  3
                                           n=1
                              on [0,π].
                            13.2        The Fourier Series of a Function



                                          Let f (x) be defined on [−L, L]. We want to choose numbers a 0 ,a 1 ,a 2 ··· and b 1 ,b 2 ,···
                                          so that
                                                                     ∞
                                                                1
                                                          f (x) = a 0 +  [a k cos(kπx/L) + b k sin(kπx/L)].  (13.1)
                                                                2
                                                                     k=1

                                        This is a decomposition of the function into a sum of terms, each representing the influence of a
                                        different fundamental frequency on the behavior of the function.
                                           To determine a 0 , integrate equation (13.1) term by term to get
                                                             1
                                                     L            L
                                                     f (x)dx =    a 0 dx
                                                             2
                                                   −L           −L
                                                                        L                   L
                                                                ∞

                                                             +      a k  cos(kπx/L)dx + b k  sin(kπx/L)dx
                                                                k=1    −L                  −L
                                                             1
                                                            = a 0 (2L) = πa 0 .
                                                             2
                                        because all of the integrals in the summation are zero. Then
                                                                          1     L
                                                                      a 0 =     f (x)dx.                        (13.2)
                                                                          L  −L
                                        To solve for the other coefficients in the proposed equation (13.1), we will use the following three
                                        facts, which follow by routine integrations. Let m and n be integers. Then

                                                                  L
                                                                  cos(nπx/L)sin(mπx/L)dx = 0.                   (13.3)
                                                                −L
                                        Furthermore, if n  = m, then

                                                 L                            L
                                                  cos(nπx/L)cos(mπx/L)dx =    sin(nπx/L)sin(mπx/L)dx = 0.       (13.4)
                                                −L                          −L



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                                   October 14, 2010  14:57  THM/NEIL   Page-429        27410_13_ch13_p425-464
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