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434    CHAPTER 13  Fourier Series

                                                 x                                       x
                                 –3   – 2  – 1   0    1    2    3        –3   – 2  – 1   0    1    2    3

                                               0                                       0
                                              –2                                      –2

                                              –4                                      –4

                                              –6                                      –6

                                              –8                                      –8

                                             –10                                      –10
                                             –12                                      –12



                                  FIGURE 13.4 Fifth partial sum of the    FIGURE 13.5 Tenth partial sum in Example
                                  Fourier series in Example 13.4.         13.4.

                                                                      x
                                                       –3   – 2  – 1  0    1     2    3
                                                                     0

                                                                    –2

                                                                    –4

                                                                    –6

                                                                    –8
                                                                   –10

                                                                   –12


                                                       FIGURE 13.6 Twentieth partial sum in
                                                       Example 13.4.


                                 and
                                                                               −1
                                                                                     n
                                                          1               (e − e )(−1) (nπ)
                                                           x
                                                   b n =  e sin(nπx)dx =−                 .
                                                                                   2
                                                                              1 + n π  2
                                                        −1
                                                   x
                                 The Fourier series of e on [−1,1] is
                                                               ∞
                                            1                       (−1) n
                                                           −1
                                                  −1
                                             (e − e ) + (e − e )            (cos(nπx) − nπ sin(nπx)).
                                            2                      1 + n π  2
                                                                       2
                                                              n=1
                                         x
                                 Because e is continuous with a continuous derivative for all x, this series converges to

                                                        e  x      for −1 < x < 1
                                                        1 (e + e )  for x = 1 and for x =−1.
                                                              −1
                                                        2
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                                   October 14, 2010  14:57  THM/NEIL   Page-434        27410_13_ch13_p425-464
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