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13.6 Complex Fourier Series  457


                             9. f has the graph of Figure 13.19.           11. f has the graph of Figure 13.21.

                                                                                              y
                                               y
                                                1
                                                                                               2
                                                                 x
                                 –3   –2  –1       1    2   3
                                                                                               1
                                                –1
                                                                                                               x
                                                                                –3       –1       1        3

                                FIGURE 13.19  f (x) in Problem 9,
                                Section 13.5.
                                                                               FIGURE 13.21  f (x) in Problem 11,
                                                                               Section 13.5.

                                                                           12. f has the graph of Figure 13.22.

                            10. f has the graph of Figure 13.20.                           y

                                             y
                                                                                          k
                                              k


                                                               x                                               x
                                        –2       2        4                      –2  –1   0     1    2    3






                                  FIGURE 13.20  f (x) in Problem 10,           FIGURE 13.22  f (x) in Problem 12,
                                  Section 13.5.                                Section 13.5.



                            13.6        Complex Fourier Series

                                        There is a complex form of Fourier series that is sometimes used. As preparation for this, recall
                                        that, in polar coordinates, a complex number (point in the plane) can be written
                                                                 z = x + iy =r cos(θ) + ir sin(θ)
                                        where

                                                                                 2
                                                                       r =|z|=  x + y 2
                                        and θ is an argument of z. This is the angle (in radians) between the positive x− axis and the
                                        line from the origin through (x, y), or this angle plus any integer multiple of 2π. Using Euler’s
                                        formula, we obtain the polar form of z:
                                                                                         iθ
                                                                  z =r[cos(θ) + i sin(θ)]=re .
                                        Now
                                                                      iθ
                                                                     e = cos(θ) + i sin(θ),



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                                   October 14, 2010  14:57  THM/NEIL   Page-457        27410_13_ch13_p425-464
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