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462    CHAPTER 13  Fourier Series



                                   This is of the form of equation (13.15) with the Cesàro filter function
                                                           Z(t) = 1 −|t| for − 1 ≤ t ≤ 1.
                                   The sequence
                                                              n
                                                                   N              N
                                                           Z                  n
                                                              N   n=−N  = 1 −    N     n=−N
                                   is called the sequence of filter factors for the Cesàro filter.



                                    This “averaging” filter damps out the Gibbs effect in the convergence of a Fourier series. To
                                 observe this, let f have fundamental period 2π, and, on [−π,π],


                                                                  −1   for −π ≤ t < 0
                                                           f (t) =
                                                                  1    for 0 ≤ t <π.
                                 The complex Fourier series of f is
                                                               ∞              n
                                                                   i −1 + (−1)
                                                                               int
                                                                               e .
                                                                   π     n
                                                            n=−∞,n =0
                                 The Nth partial sum of this series is
                                                                  N              n
                                                                      i −1 + (−1)

                                                                                   int
                                                         S N (t) =                e .
                                                                      π     n
                                                               n=−N,n =0
                                 If we pair positive and negative values of n in this summation, we find that
                                                               N
                                                                  −2

                                                                              n
                                                        S N (t) =   (−1 + (−1) )sin(nt).
                                                                  nπ
                                                               n=1
                                                        n
                                                                                   n
                                 If N is even, then −1 + (−1) = 0. If N is odd, then −1 + (−1) =−2. Therefore, for odd N,
                                                    4         1         1             1
                                             S N (t) =  sin(t) +  sin(3t) +  sin(5t) + ··· +  sin(Nt) .
                                                    π         3         5             N
                                 The Nth Cesàro sum is
                                                            N
                                                                                       n
                                                                           i  −1 + (−1)
                                                                      n                  int
                                                   σ N (t) =     1 −                    e .
                                                                     N    π       n
                                                         n=−N,n =0
                                 With some manipulation, this can be written
                                                          N
                                                                 n       −2     −1 + (−1) n
                                                   σ N (t) =  1 −                    sin(nt).
                                                                 N     π       n
                                                          n=1
                                    Figure 13.24 shows graphs of S 10 (t) and σ 10 (t), and Figure 13.25 graphs of S 30 (t) and σ 30 (t),
                                 showing the Gibbs effect in the partial sums of the Fourier series, and this effect damped out in
                                 the smoother Cesàro sums. The Cesàro filter also damps out the higher frequency terms in the
                                 Fourier series because 1 −|n/N| tends to zero as n increases toward N.




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                                   October 14, 2010  14:57  THM/NEIL   Page-462        27410_13_ch13_p425-464
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