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                                                 12.7 EXAMPLES OF SIGNIFICANCE OF K p



                            is known, the ratio of the partial pressures in the equilibrium state is known. It would be
                  Thus, if K p r
               convenient to manipulate this expression into a more useful form. Consider the general reaction
               equation for the carbon monoxide and oxygen reaction (eqn (12.27))
                                            1                        a
                                       CO þ O 2 5 ð1   aÞCO 2 þ aCO þ O 2
                                            2                        2
               then
                                                       p    1   a  p
                                                  n CO 2
                                                ¼        ¼
                                            p rCO 2
                                                   n p p 0  1 þ a=2 p 0
                                                  n CO p     a    p
                                            p rCO ¼     ¼                                  (12.71)
                                                   n p p 0  1 þ a=2 p 0
                                                     p     a=2   p
                                                 n O 2
                                               ¼       ¼
                                            p rO 2
                                                  n p p 0  1 þ a=2 p 0
                                       can be related to the degree of dissociation, a, through the following
                  Hence, the value of K p r
               equation
                                                          p                    p
                                                s ffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi   s ffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi
                                   1   a 1 þ a=2  1 þ a=2   ffiffiffiffiffi  1   a  1 þ a=2  ffiffiffiffiffi
                                                            p 0
                                                                                p 0
                                ¼                         p ffiffiffi ¼              p ffiffiffi :    (12.72a)
                             K p r
                                  1 þ a=2   a       a=2     p     a      a=2     p
               and
                                                    s ffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi
                                               1   a  1 þ a=2 1    K p r
                                          K p ¼              p ffiffiffi ¼ p ffiffiffiffiffi              (12.72b)
                                                a      a=2     p    p 0
                                          and a allows the degree of dissociation, a, to be evaluated if K p is
                  The relationship between K p r
               known. Equation (12.72) shows that, for this reaction, the value of K p is a function of the degree of
               dissociation and also the pressure of the mixture. This is because the amount of substance of products
               is not equal to the amount of substance of reactants.

               12.7.2 EXAMPLE 2
               Consider the water–gas reaction:

                                              CO 2 þ H 2 5 CO þ H 2 O                      (12.73)
                  By the law of mass action
                                         p rCO p rH 2 O
                                    K p r  ¼
                                          p rCO 2  p rH 2
                                                                                           (12.74)

                                           x CO x H 2 O  1þ1 1 1  x CO x H 2 O
                                       ¼            p       ¼           ¼ K p
                                               x                   x
                                           x CO 2 H 2          x CO 2 H 2
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