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348    CHAPTER 16 RECIPROCATING INTERNAL COMBUSTION ENGINES




                                                   1        p 1 Q 0 v

                                         p ¼  1    k 1                                    (16.8)
                                          i
                                                  r              1
                                                        RT 1 ε 1
                                                                 r
                Equation (16.8) shows that the imep is directly proportional to the trapped pressure (p 1 ), if all other
             parameters remain constant. Hence the rating of an engine can be increased by pressurizing the inlet
             manifold (e.g. by turbocharging) at constant air–fuel ratio – in reality, the amount of fuel added has
             increased in proportion with the amount of air trapped in the cylinder.
                Similar results can be evaluated for diesel and dual combustion cycles, and these will just be quoted
             here
             1. Diesel cycle (see Fig. 3.14)

                                                             k
                                             W        1     ðb   1Þ
                                       h ¼      ¼ 1    k 1          ;
                                        th
                                            Q 23     r      kðb   1Þ
             and
                                              1    b   1        p 1 Q p
                                                    k              0
                                   p ¼   1                              ;                 (16.9)
                                    i
                                            r k 1  kðb   1Þ           1
                                                             RT 1 ε 1
                                                                      r
             where Q is the negative of the enthalpy of reaction of the fuel, because the energy is added at constant
                    0
                    p
             pressure.
             2. Dual combustion cycle (see Fig. 3.15)
                                                           k
                                               1        ðab   1Þ
                                     h ¼ 1     k 1                    ;
                                       th
                                              r    ðakðb   1Þþða   1ÞÞ
             and
                                         1        ðab   1Þ            p 1 Q p
                                                     k                   0
                               p ¼   1    k 1                                            (16.10)
                                i
                                        r    ðakðb   1Þþða   1ÞÞ           1
                                                                  RT 1 ε 1
                                                                           r
                                                            0
                                                                 0
                It has been assumed in deriving Eqn (16.10) that Q ¼ Q ; this is not unreasonable since the
                                                            p    v
             differences between these values are usually very small – see Chapter 10.
              Example 16.2.1
                Evaluate the cycle efficiency and imep of a petrol engine operating at an air–fuel ratio of 15:1 with
             a trapped pressure of 1 bar and trapped temperature of 100 C. Consider compression ratios of 7 and

             12:1 and evaluate the maximum cycle pressure.
                Thermal efficiency of a constant volume cycle is given by:
                                                          1
                                                h ¼ 1
                                                 th
                                                        r k 1
                Thus the thermal efficiency at r ¼ 7is h ¼ 0:5408, and at r ¼ 12 is h ¼ 0:6299:
                                                                          th
                                                 th
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