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21.3 EFFICIENCY OF A FUEL CELL       515





                  This shows that the potential of the hydrogen–oxygen fuel cell increases with pressure. This is
               similar to the effect of pressure on the hydrogen–oxygen combustion reaction, when dissociation
               decreased from 0.0673 to 0.0221 as the pressure was increased from 1 bar to 100 bar for the stoi-
               chiometric combustion of methane in Chapter 11. Hence, if the number of moles of reactants is not
               equal to the number of moles of products then the emf of the cell will be a function of the pressure of
               operation.

               21.3 EFFICIENCY OF A FUEL CELL

               The fuel cell is not 100% efficient, and it is possible to define its efficiency by the following equation
                                           Maximum useful work output  w use
                                       h ¼                         ¼                       (21.46)
                                                Heat of reaction      Q p
                  Now the maximum useful work output obtainable is defined by the change of Gibbs energy, i.e.
                             w use ¼ DG ¼ G products   G reactants
                                                          0                  1
                                           0         0            0
                                     X         X             X         X                   (21.47)
                                 ¼       H          H   T @      S         S f 0 A
                                                                  f
                                                     f
                                           f
                                    products  reactants     products  reactants
                                    X     0    X     0
               and            Q p ¼      H         H f                                     (21.48)
                                          f
                                   products   reactants
                  Thus, the efficiency is
                                                           1

                                           X     0   X
                                       T        S         S f 0 A
                                                 f
                                          products  reactants      TDS       TDS
                               h ¼ 1 þ    X     0   X     0   ¼ 1      ¼ 1 þ               (21.49)
                                              H          H f        Q p       Q 0 p
                                                f
                                         products  reactants
                  The last expression in Eqn (21.49) has been written in terms of the calorific value of the fuel
               because this is usually positive, and hence the efficiency is defined by the sign of the change of entropy.
               If the entropy change is positive then the efficiency is greater than unity: if it is negative then it is less
               than unity. Consider now the hydrogen–oxygen reaction described above. If the fuel cell is maintained

               at the standard temperature of 25 C, and the processes are assumed to be isothermal then

                                DG ¼ h  0 f    T s H 2 O   s H 2    0:5s O 2
                                          H 2 O
                                                                                           (21.50)
                                    ¼ 241820   298ð188:71   130:57   0:5   205:04Þ
                                    ¼ 228594:8kJ=kmol
               and Q p ¼ 241820 kJ/kmol. Hence the efficiency is
                                                   228594:8
                                               h ¼         ¼ 0:945                         (21.51)
                                                   241820
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