Page 72 - Advances in Textile Biotechnology
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Developments in enzymatic textile treatments   51


                                 2 αψ + β
                   Γ ES =ψ −
                            ⎛ β   ⎞  −( αψ β                            [2.45]
                            ⎜  +α ⎟ e      +α
                                     2
                                        + )t
                            ⎝ψ    ⎠
            where
                       −+    β − 4 αγ
                        β
                              2
                   ψ =                                                  [2.46]
                             2 α
              If the amount of adsorbed enzyme is small compared with the amount
            available in the liquid bulk, the model becomes simpler. In that case, it may
            be assumed that the enzyme concentration in the bulk is constant and equal
            to C E,0  so that equation [2.37] becomes:
                      d*
                   A C   ES  =  kV C E,0 A C *  E  k A C * −  des  ES   [2.47]
                              ads
                                 C
                         t d
              Substitution of equation [2.39] and simplifi cation gives:
                    d*
                                                      des *
                      ES  =  kV C C E,0 *  ES,max −( k ads V C E,0 + k )  ES  [2.48]
                           ads
                                               C
                     dt
              Equation [2.48] describes the dynamics of the adsorption process when
            the enzyme concentration in the capillary liquid does not change as a result
            of the adsorption process, which is the case when there is an excess
            of enzymes in the solution.  This differential equation can be solved by
            separation of the variables. Its solution with the initial conditions  t  = 0,
            Γ ES  = 0 reads:

                          ads
                   * ES =  kV C C E,0 * ES,max  ⎣ 1 ⎡ ⎡  −  e −(k ads C E,0 +V C  k des  t )  ⎤ ⎦  [2.49]
                         kV  C C E,0 + k des
                          ads
              For equations [2.45] and [2.49] we have performed some calculations to
            show clearly the effect of the decreasing enzyme concentration in the cap-
            illary liquid during adsorption of enzymes at the capillary wall. For the
            example we have used values calculated earlier:
                         −10
            •  A C  = 6 × 10  m 2
                         −16
            •  V C  = 3 × 10  m 3
            •  C E,0  = 0.1 mol m −3
                             −8
            •  Γ ES,max  = 6.7 × 10  mol m −2
            The values for the adsorption and desorption coefficients have been

                                                     −1
                                     −1 −1
                                15
            estimated to be: k ads  = 10  mol  s  and k des  = 0.5 s . The results are expressed
            as the fraction of the adsorption sites that are occupied by enzyme mole-
            cules  Γ ES /Γ ES,max  as a function of time. Figure 2.13 shows the results


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