Page 150 - Aerodynamics for Engineering Students
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Potential flow  133


              3.3.10  A spinning cylinder in a uniform flow
              This is given by the stream function due to a doublet, in a uniform horizontal flow,
              with a line vortex superimposed at the origin. By adding these cases
                                          P             I’r
                                     $=-sine-      Uy--1n-
                                         2rr            2r   ro
              Converting to homogeneous coordinates



              but from the previous case d  m  = a, the radius of the cylinder.
                Also since the cylinder periphery marks the inner limit of the vortex flow, ro  = a;
              therefore the stream function becomes:
                                                                                 (3.46)


              and differentiating partially with respect to r and 0 the velocity components of the
              flow anywhere on or outside the cylinder become, respectively:
                                        @
                                  qt =--=  Usin0
                                        ar                                       (3.47)
                                       1w
                                  q  ---=ucos0
                                   n-r  8tI
              and

                                            4 = dq; + 4:

              On the surface of the spinning cylinder r = a. Therefore,
                                               qn  = 0
                                                        r
                                          qt = 2U sin 0 + -                      (3.48)
                                                       27ra
              Therefore
                                                          r
                                        q = qt = 2U sin 0 + -
                                                         2ra
              and applying Bernoulli’s equation between a point a long way upstream and a point
              on the cylinder where the static pressure is p:







              Therefore

                                               1-  2sin0f-
                                 p-po=-pU    2[  (         2rua >’               (3.49)
                                         2
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