Page 259 - Aerodynamics for Engineering Students
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242  Aerodynamics for Engineering Students
                   Writing the numerator as (z - zl) + z1:


                                     =$[I
                                                                    dz
                                                       +zl
                                              sdz
                                                           Js
                                       47rs  -s&E-7  -sd?Zf(z-z1)          1
                   Evaluating the first integral which is standard and writing I for the second
                                                     TO
                                               wz, =-[7r+z1l]                         (5.40)
                                                     47rs
                   Now as this is a symmetric flight case, the shed vorticity is the same from each side of
                   the wing and the value of the downwash at some point z1 is identical to that at the
                   corresponding point - z1  on the other wing.
                     So substituting for fzl in Eqn (5.40)  and equating:




                   This identity is satisfied only if I  = 0, so that for any point z - z1  along the span
                                                        r0
                                                    w=-                               (5.41)
                                                        4s
                   This important result shows that the downwash is constant along the span.


                   Induced drag (vortex drag) for elliptic distribution
                   From Eqn (5.36)




                   whence
                                                        A
                                                           2
                                                  D~ = -pro                           (5.42)
                                                        8
                   Introducing
                                                         1
                                                Dv = Co,-pV2S
                                                         2
                   and from Eqn (5.39)
                                                       e, vs
                                                  ro =-
                                                         TS
                    Eqn (5.42)  gives
                                            eo, - P v2s = 5 P ( F)
                                                1
                                                            CLVS
                                               2
                    or


                                                                                      (5.43)
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