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6.5 Filtration                                                  181

                                                  Q
                                         U 1
                                   U 0 ¼     ¼                           ð6:90Þ
                                        1   a  ð 1   aÞA c
              The number concentration of particles lost per unit volume from the bulk air
            over the distance dx equals to that captured by the fiber with a single fiber efficiency
            g corresponding to an approaching flow rate of U 0 d f   ds f ; where d f   ds f defines
             sf
            the cross section area of the fiber with the length of ds f and the diameter of d f .

                              Q   dC N ðxÞ¼ g C N ðxÞU 0 d f   ds f      ð6:91Þ
                                             sf
                                                        3
            where C N is the number concentration of particles (#/m ), the single fiber efficiency
            g is determined by Eq. (6.87).
             sf
              The LHS stands for the decrease in particle number per unit time after air passes
            through the bulk filter thickness dx, whereas the RHS stands for the reason of this
            decrease calculated as if all these particles passed through a single fiber with a cross

                                  with an approaching speed of U 0 and a single fiber
            section area of d f   ds f
            efficiency of g . Equations (6.88) and (6.91) give,
                       sf
                                                        4aA c   dx
                         A c U 1   dC N ðxÞ¼ C N ðxÞg U 0 d f
                                                 sf          2
                                                           pd
                                                             f
                                                                         ð6:92Þ

                                 dC N ðxÞ    U 0 g 4a
                                                 sf
                                       ¼             dx
                                 C N ðxÞ    U 1 pd f
              Consider Eq. (6.90), we have

                                  dC N ðxÞ     g 4a
                                                sf
                                        ¼             dx                 ð6:93Þ
                                  C N ðxÞ    ð 1   aÞpd f
              At any instant, all the parameters in the bracket on the right-hand side are
            constants for the particle size of d p , which allows us to integrate from inlet to outlet
            of the filter:
                                C Z No dC N xðÞ  Z L     g 4a
                                                  sf
                                         ¼              dx               ð6:94Þ
                                   C N xðÞ     ð 1   aÞpd f
                                C Ni       0
            which gives the overall fractional penetration through the filter

                                                    sf
                                       C No        g 4aL
                               Pd p ¼      ¼ exp                         ð6:95Þ
                                       C Ni      ð 1   aÞpd f
              Consequently, we can get the overall fractional filtration efficiency of the filter as
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