Page 162 - Air and Gas Drilling Manual
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5-4    Air and Gas Drilling Manual
                                   Unless field test data are available that give the actual rock specific gravity, the
                               approximate average specific gravity for sedimentary rock is  assumed to  be 2.7,  the
                               average  specific  gravity  for  igneous  rock  is  assumed  to  be  2.8,  and  the  average
                               specific gravity for metamorphic rock is assumed to be 3.0 [1].
                                   Illustrative Examples  5.1,  5.2a,  and  5.3a  describe  the  implementation  of  the
                               basic planning steps Nos. 1 through 6 given in Section 5.1 above.
                                   Illustrative Example 5.1  Using the basic equations above, determine the direct
                               circulation minimum  volumetric flow rate  for  a  well  with  a  4  1/2  inch  openhole
                               borehole (4 1/2 inch drill bit diameter) and a uniform drill string composed of a drill
                               pipe outside diameter of 2  3/8 inch.    The anticipated drilling  rate in  a sequence of
                               competent unfractured limestone rock (sedimentary rock) is  assumed to  be 30 ft/hr.
                               The drilling depth is 1,000 ft.
                                   In order to be able to calculate air drilling  conditions at other surface elevations
                               above sea level, all calculations to obtain values like the minimum  volumetric flow
                               rate are carried out  for a baseline sea level atmosphere.  For these  calculations  and
                               most of those in this treatise the baseline sea level atmosphere is the API Mechanical
                               Equipment  Standards  standard  atmospheric  conditions  (see  Chapter  4).    These
                               conditions  are  a  pressure  of  14.696  psia  and  a  temperature  of  60˚F.    Thus,  the
                               pressure of the gas (in this case air) that flows into the compressor, P at, is
                                             .
                                      p at  = 14 696 psia
                                      P at  =  p 144
                                             at
                                                    2
                                            ,
                                      P  = 2 116 lb/ft abs
                                       at
                               The atmospheric temperature of the gas (air) that flows into the compressor, T at,  that
                               will supply the drilling operation is
                                             o
                                      t  = 60 F
                                       at
                                      T at  =  t at  + 459 67
                                                   .
                                                 o
                                              .
                                      T at  = 519 67 R
                               Thus, P g and T g become
                                      P =  P  = 2 116 lb/ft abs
                                                         2
                                                  ,
                                       g    at
                                      T =  T  = 519 67 R
                                                      o
                                                   .
                                       g    at
                               Using Equation 4-11, the specific weight of the gas entering the compressor is
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