Page 166 - Air and Gas Drilling Manual

5-8 Air and Gas Drilling Manual
π
π
 
(.005
0
)
0
0
 
 
4
4
=
e
π
π
 
 
av
+
(. 0 198
(. 0 375
)
  (.375 ) 2 ) 2 + (.0 00015 )   2 (.198 ) 2
 
4
4
e av = 0 0039 ft
.
Equation 5-5 becomes
  2
 
f =   1   
.
.

.
2 log  0 375 − 0 198  +114 
   0 0039   
.
.
f = 0 051
With the above values Equation 5-2 becomes
a =  10 .    1 +  0 155.   
a
 53 36    0 408.  
.
.
a a = 0 026
and Equation 5-3 becomes
0 408)
.
b a = 0 051  53 36.  2 (. 2
π
(
2 32 2) ( 0 375 − 0 198. )  10.    2 [ 2 2 ] 2
.
.
0 375)
(.
  (. − 0 198)
4
b a = 331 6
.
Equation 5-1 becomes
 2 (. 0 026 ) ( , 1 000 )  . 05
[


. (523 67
. (523 67
P bh =  ( , 2 116 ) 2 + 331 6 . ) 2 ] e 523 .67 − 331 6 . ) 2 
 


2
P bh = 3 792 lb/ft abs
,