Page 273 - Air and Gas Drilling Manual
P. 273

6-18    Air and Gas Drilling Manual
                                                           2
                                                          
                                                 f
                                                         R
                                         =
                                                     p)
                                                h (
                                      b
                                                        
                                                         S 
                                                              π
                                       a
                                                              
                                            gD −
                                                    D
                                           2
                                                                        2
                                                                2  D (  w ˙ h 2 g 2  −  D p) 2  (6-53)
                                                              4
                                   In the above form, both  sides of Equation 6-51 can be  integrated.    Using  the
                               constants in Equations 6-52 and 6-53 the solution to Equation 6-51 is
                                          ln P (  2  +  b T av)  =  a  h               (6-54)
                                       1                 P bh  a     H
                                                     2
                                       2           a          T av   0
                                                         P at
                               Evaluating Equation 6-54 at the limits and rearranging the results gives
                                         P 2  +  b T   2  a
                                                  2
                                      ln   bh  a  av   =  a  H                       (6-55)
                                                  2
                                           P at 2  +  b T    T av
                                                a
                                                  av
                               Raising both sides of Equation 6-55 to the natural exponent, e, gives
                                                       a
                                      P 2  +  b T  2  2  aH
                                       bh    a  av  =  e  T av                         (6-56)
                                       P  2  +  b T  2
                                       at    a  av
                               Equation 6-59 can be rearranged and a solution obtained for P bh.  This yields
                                                        2  aH        05 .
                                                           a
                                                              −
                                                      2
                                      P bh  =    P (  at 2  +  bT av)  ebT av 2     (6-57)
                                                           T av
                                                   a
                                                                 a
                                                                    
                                   The flow of gas to the well must be sufficient to  carry solid  rock cuttings from
                               the bottom  of the annulus to  the  surface.    Therefore,  it  is  assumed  that  the  flow
                               condition in  both  the annulus and the inside of the drill  string  is  turbulent.    The
                               empirical von Karman relationship for determining the Fanning friction factor for the
                               annulus is
                                                                  2
                                                                
                                      f =       D − 1                              (6-58)
                                                       D 
                                                
                                           2 log.               
                                                        p
                                                   h
                                                           + 1 14
                                                  e         
                                                                
                                   For follow-on calculations for flow in  the  annulus  the  absolute  roughness  for
                               commercial pipe, e p =  0.00015  ft,  will  be used for the outside surfaces of the drill
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