Page 351 - Air and Gas Drilling Manual
P. 351

8-34    Air and Gas Drilling Manual
                                                                        π
                                                   π
                                                   
                                            (.
                                             001)
                                                      0 656)
                                                                0 00015)
                                                                           0 375)
                                                                        4 
                                                                       
                                                   4 
                                                  
                                          =
                                      e
                                                                 π
                                                    π
                                       av3
                                                              +
                                                                     0 375)
                                                        0 656)
                                                    4 
                                                                 4 
                                                                
                                                      (. (.  2  2 + (.    (.    2  (.  2
                                      e av3  =  0 0076 ft
                                             .
                               Equation 6-58 becomes
                                                                     2
                                                                    
                                      f a3  =     0 656 − 1  0 375    
                                             2   log   .  .   + .
                                                                  114
                                                  
                                                   0 0076         
                                                       .
                                      f   =  0 055
                                             .
                                       a3
                               With the above values Equations 6-52 and 6-53 become, respectively,
                                                         0 950  
                                              10      .
                                               .
                                      a a3  =   53 36     1 +   .   
                                                         2 635 
                                               .
                                      a a3  =  0 025
                                             .
                               and
                                                                              2 635)
                                                   .
                                                                 .
                                     b a3  =      0 055         53 36   2   (.   2
                                                  0 656 −
                                                                       π
                                          2 32 2) ( .    0 375  )  10      2 [  2     2 ] 2
                                                                 .
                                                          .
                                            (
                                              .
                                                                                     0 375)
                                                                            0 656)
                                                                        4   (.  − (.
                                             ,
                                      b a3  =  11 490
                               Equation 6-58 becomes
                                                                                          
                                                               2 0 025) ( ,            2  05 .
                                                                       2 375)
                                                                  (.
                                        [
                                                                      .
                                                                               ,
                                                                                   (
                                                                                         )
                                                                                      .
                                         11 640)
                                                   ,
                                                       (
                                 P a3  =  ( ,  2  +  11 149 586 29)  2 ]  e  586 29  −  11 149 586 29 
                                                           .
                                                                                        
                                                                                          
                                                     2
                                      P a3  =  16 030 lb/ft abs
                                             ,
                                            P a3
                                      p   =
                                       a3
                                            144
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