Page 352 - Air and Gas Drilling Manual
P. 352

Chapter 8: Air, Gas, and Unstable Foam Drilling    8-35
                                          =
                                            111 3 psia
                                      p
                                               .
                                       a3
                                   The  fourth  annulus  seciton  increment  is  denoted  by  the  length  H 4.    The
                               temperature at the bottom of the length H 4 in  the openhole annulus section (bottom
                               of the drill pipe tool joints lumped geometry), T 4, is
                                      T =  T +  001 ( H +  H  +  H +  H )
                                                 .
                                       4    r         1    2    3     4
                                      T =  T +  0 01 9 500)
                                                     ,
                                                 .
                                                    (
                                            r
                                       4
                                      T =  599 41 R
                                                o
                                              .
                                       4
                               The average temperature of this openhole annulus section H 4 is
                                             T +  T
                                      T av4  =  3  4
                                               2
                                                 o
                                               .
                                      T av4  =  598 79 R
                               Using Equation 8-2, the average absolute surface roughness of this  annulus section,
                               e av4, is
                                                                        π
                                                   π
                                                                      
                                                                           0 552)
                                                      0 656)
                                                                0 00015)
                                             001)
                                             (.    4   (.  2  + (.    4   (.  2
                                      e av4  =
                                                                 π
                                                    π
                                                          2  +        2
                                                                     0 552)
                                                        0 656)
                                                     4   (.     4   (.
                                             .
                                      e av4  =  0 0059 ft
                               Equation 6-58 becomes
                                                                     2
                                                                    
                                      f a4  =     0 656 − 1  0 552    
                                             2   log   .  .   + .
                                                                  114
                                                  
                                                   0 0059         
                                                       .
                                             .
                                      f a4  =  0 076
                               With the above values Equations 6-52 and 6-53 become, respectively,
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