Page 150 - Aircraft Stuctures for Engineering Student
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134  Bending of thin plates

                  Mxy + (dMx,,/dy)Sy. At the common surface of the two adjacent elements there is
                  now a resultant force (aMx,,/ay)by or a vertical force per unit length of aMxy/ay.
                  For the sign convention for Q, shown in Fig. 5.9 we  have a statically equivalent
                  vertical force per unit length of (Q, - 8Mx,,/ay). The separate conditions for a free
                  edge of  (Mxy)x=o = 0 and  (Qx)x=o  = 0  are  therefore replaced  by  the  equivalent
                  condition

                                             (ex-%)      x=o  =O


                  or in terms of deflection


                                                                                     (5.25)

                  Also, for the bending moment along the free edge to be zero


                                                                                     (5.26)

                    The replacement of the twisting moment Mxy along the edges x = 0 and x = a of a
                  thin plate by a vertical force distribution results in leftover concentrated forces at the
                  corners of Mxy as shown in Fig. 5.11. By the same argument there are concentrated
                  forces  Myx produced  by  the  replacement  of  the  twisting  moment  Myx. Since
                  Mxy = -My,,  then resultant forces 2Mxy act at each corner as shown and must be
                  provided  by  external supports  if  the  corners  of  the  plate  are  not  to  move.  The
                  directions of  these forces are easily obtained if the deflected shape of the plate is
                  known. For example, a thin plate simply supported along all four edges and uni-
                  formly loaded  has awlax positive and numerically increasing, with  increasing y
                  near  the corner x = 0, y  = 0. Hence #w/axay  is positive at this point  and from
                  Eq. (5.14) we see that Mxy is positive and Myx negative; the resultant force 2Mv  is
                  therefore downwards. From symmetry the force at each remaining corner is also
                  2Mxy downwards so that the tendency is for the corners of the plate to rise.
                    Having discussed various types of boundary conditions we shall proceed to obtain
                  the solution for the relatively simple case of a thin rectangular plate of dimensions
                  a x b, simply supported along each of its four edges and carrying a distributed load
                  q(x, y). We have shown that the deflected form of the plate must satisfy the differential
                  equation

                                         a4w     a4w    a4w   q(x,y)
                                         -+2-+-=-
                                         a#     ax~ay2  ay4     D
                  with the boundary conditions
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