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11.5 Constraint of  open section beams  473




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               Fig. 11.30  Section of axially constrained open section beam under torsion.


                 The beam is loaded by a pure torque so that the axis of twist passes through the
               shear centre S(R) of each section. We shall take the origin for s at the point  1 and
               initially plot 2AR-o against s to determine rR (see Fig.  11.31). The position of  the
               centre of gravity, (2A’,), of the wire 1’2’3‘4’ is found by taking moments about the
               s axis. Thus

                                               (3 (7)  (hqd)
                               t(2d+h)2A’,  = td  - + th  - + rd  -

               from which
                                                  hd(h + d)
                                            3A‘,  =
                                                  2(h + 2d)
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