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160   CHAPTER 4 LINEAR PROGRAMMING APPLICATIONS



                                      Table 4.9 Petroleum Cost and Supply for the DOC Blending Problem
                                      Petroleum Component             Cost/litre          Maximum Available
                                               1                       $0.50                  5 000 litres
                                               2                       $0.60                 10 000 litres
                                               3                       $0.84                 10 000 litres





                                      Table 4.10 Product Specifications for the DOC Blending Problem

                                      Product                                             Specifications
                                      Regular fuel                                    At most 30% component 1
                                                                                      At least 40% component 2
                                                                                      At most 20% component 3
                                      Premium fuel                                    At least 25% component 1
                                                                                      At most 40% component 2
                                                                                      At least 30% component 3




                                       We develop the objective function of maximizing the profit contribution by
                                     identifying the difference between the total revenue from both fuels and the total
                                     cost of the three petroleum components. By multiplying the $1.00 per litre price by
                                     the total litres of regular fuel, the $1.08 per litre price by the total litres of premium
                                     fuel, and the component cost per litre figures in Table 4.9 by the total litres of each
                                     component used, we obtain the objective function:

                                                  Max  1:00ðx 1r þ x 2r þ x 3r Þþ 1:08ðx 1p þ x 2p þ x 3p Þ
                                                         0:50ðx 1r þ x 1p Þ  0:60ðx 2r þ x 2p Þ  0:84ðx 3r þ x 3p Þ

                                     When we combine terms, the objective function becomes:
                                                Max 0:50x 1r þ 0:40x 2r þ 0:16x 3r þ 0:58x 1p þ 0:48x 2p þ 0:24x 3p
                                       The limitations on the availability of the three petroleum components are:

                                                           x 1r þ x 1p   5 000 Component 1
                                                           x 2r þ x 2p   10 000 Component 2
                                                           x 3r þ x 3p   10 000 Component 3
                                       Six constraints are now required to meet the product specifications stated in
                                     Table 4.10. The first specification states that component 1 can account for no more
                                     than 30 per cent of the total litres of regular fuel produced. That is,

                                                               x 1r   0:30ðx 1r þ x 2r þ x 3r Þ
                                     Rewriting this constraint with the variables on the left-hand side and a constant on
                                     the right-hand side yields:

                                                             0:70x 1r   0:30x 2r   0:30x 32   0
                                     The second product specification listed in Table 4.10 becomes:
                                                               x 2r   0:40ðx 1r þ x 2r þ x 3r Þ






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