Page 95 -
P. 95

Mud Pumps                                                      71



           Table 3.4 (Continued )
           Input Data                        1
           Pipe roughness                    0.0025 in
           Length of drill collar 1          60 ft
           OD of collar 1                    7.000 in
           ID of collar 1                    3.000 in
           Length of drill collar 2          0 ft
           OD of collar 2                    6.250 in
           ID of collar 2                    2.500 in
           Length of drill collar 3          250 ft
           OD of collar 3                    5.750 in
           ID of collar 3                    3.000 in
           Drill pipe OD                     5.000 in
           Drill pipe ID                     4.000 in
           Mud weight                        11 ppg
           Plastic viscosity                 5 cp
           Yield point                       5 lb/100 ft 2
           Mud flow rate                     300 gpm
           Pressure drop at mud motor        200 psi
           Flow rate exponent                1.75 m
           Solution                          Casing Pipe    Hole Pipe
                    q
           v =      2   2                    3.25 ft/s      3.31
                    o   i
              2:448ðd − d Þ
                                             2.38 in        2.35
           d e = 0:816ðd o − d i Þ
           μ = μp +  6:66τ y d e             29.44 cp       28.60
                      v
            a
           N Re =  928ρ vd e                 2,683          2,719
                     f
                   μ
                    a
                    (
                        ε     5:0452
           f = −4 log       −       log      0.0137         0.0137
                      3:7065   N Re
                  1:1098              −2
                ε     +    7:149   0:8981
                2:8257   N Re
                f ρ v 2
           dp f  =  f  arcsin θ              0.026 psi/ft   0.027
           dL   25:8d

           p f =  dp f  L                    181 psi        73
                dL
                 n
                                             1,259 psi
           Δp d = ∑ p fi
                i = 1

           p p = ðm + 1Þ Δp d                3,461 psi
           p p =  m + 2  Δp d π
                2                            2,360 psi
                                                              (Continued )
   90   91   92   93   94   95   96   97   98   99   100