Page 86 - Applied Process Design For Chemical And Petrochemical Plants Volume II
P. 86

Distillation                                           75


               8. Calculate internal vapor and liquid flows.
                 (LJD)min  = assumed

                 Solve for (L,/V,) min

                                                         (8- 143)


                 L, - (number) (I7,) = (Lr/D)mk(D)
                 D is known
                 Calculate  V,  and L,  from above.
                 In stripping section:                                   Because  the  second term  of  the  denominator is
                 Solve directly for L,                                 usually negligible when the light key in the bottoms is
                                                                       very  small; less  than  0.1 mol  fraction, this  term  is
                 L,  = L,. + qF                                        often omitted.

                 Solve for Vs:

                                                         (8- 144)
                                                                         lvote that these calculations are made for the light
                                                                       key, 1; heavy key, h; and all components heavier than
                 Calculate L,/B                                        the heavy key,  H.  For split key systems, the calcula-
               9. Evaluate pinch compositions at the assumed temper-   tions are made for all components heavier than the
                 atures of  Step 7. If this temperature does not give a   light key.
                 balance, other temperatures should be assumed and   10. Calculate mol fraction ratio:
                 a balance sought as indicated below. Either of the fol-   (a) Stripping pinch
                 lowing balances can be used,  depending upon  the
                                                                             light key
                 convenience of the designer:                            r=
                 Rectifying:                                             ps  heavy key
                                                                        (b) Rectifying pinch

                                                                             light key
                                                                         rpr  =
                                                                             heavy key
                                                                        (c) p = rpshpr
                                                                     11. Calculate for each component in pinch.
                                                                           Rectifying: apply only to components lighter than
                                                                         light key, i = L’

                                                                         (ai - 1) ai
                   When the heavy key in the overhead is very small,
                 less than 0.1 mol fraction, the last term of the denom-    ai
                 inator can be omitted.
                                                                           Read from Figure 848 value of C,i  for each com-
                                                                         ponent.
                                                                        Calculate for each component:
                                                                         (Cni) kPr)
                   Kote that the calculations are only made for the
                 heavy key, h; light key, I; and all components lighter   Sum these values:
                 than it, L’. If there are split keys, the calculation is to
                 include all components lighter than the heavy key.      2,Gi xip
                 Stripping pinch compositions:                          i=L
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