Page 105 - Applied Process Design for Chemical and Petrochemical Plants Volume I
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92                       Applied Process Design for Chemical and Petrochemical Plants

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             Figure 2-23. Pressure drop in liquid
             lines.  By  permission  Crane  Co.,
             Technical Paper #470,  Engineering
             Div., 1957. Also see 1976 edition.


             The friction  loss or pressure  drop, FD,  is determined  at   where  P,  = system end pressure = 22 + 15 = 37 psig (not
             the design flow rate, QD, for the piping, valves, and fric-     friction)
             tion producing equipment (such as tubular heat exchang-     Piping system pipe friction @ QD flow rate = 6 psi
             ers,  tubular  furnaces/heaters) , orifice  or other  meters,   Heater, friction = 65 psi
             and control valves. Because the  system friction  pressure   Separator, friction = 1 psi
             loss changes with flow rate through the system, recogni-    Preheaters, 10 + 12 (friction) = 22 psi
             tion must be given to the changes in flow rate (increase or   Orifice, allow, friction = 2 psi
                                                                         Total friction, excluding control valve, FD = 96 psi
             decrease) as it affects the pressure  loss through the con-
             trol valves. For any design, the beginning and end points   Assume pressure loss through control valve  = 35 psi
             of  the  system  should  be  relatively  constant  for  good
             process operations.                                   Then APc = (Ps - P,)  - FD, psi              (2-59)
               For good control by the valve, the pressure drop across
             (or through) the valve must always be greater than the fric-   35  = (Ps - 37) - 96
             tion losses of the system by perhaps 10% to 20% (see [9]).
                                                                     Ps  = 168 psi, at pump discharge, using assumed control
                                                                         valve pressure drop of 35 psi
             Example 2-3: Establishing Control Valve Estimated
             Pressure Drop, using Cormell's Method [9].            Note that P,  = 22 psig + 15 psi static Hd. = 37 psig
                                                                     Assume  that  allowances  must  be  made  for  a  10%
               Refer to Figure 2-26 for an example to determine the   increase in process flow rate, above design, QD. Pressure
             pressure loss (drop) through the control valve.       drop varies as the square of the flow rate.
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