Page 113 - Applied Process Design for Chemical and Petrochemical Plants Volume I
P. 113
100 Applied Process Design for Chemical and Petrochemical Plants
SHEET NO.
LUDWIG CONSULTING ENGINEERS
BY ABC LINE SIZE SHEET Job No.
Date Charge No.
LP - 51
Line NO. Flow Sheet Drowipg No.
~
~
~i~~ ~ Reactor ~Discharge ~ i ~ ~ i ~ ~
Fluid in line Crude Product Temperature 280 OF
GPM (Calc.) 23.7 GPM (des.) 25 Pres sure 350 psig
CFM (Calc.) CFM (des.) Sp. Gr.O.93 -
L b s . /hr. (C a I c. ) L bs./hr.(des.) sp. VOl. cu.ft./lb.
S
Recommended Velocity 6.0 fP ___ Viscosity 0.91 CP
Straight pipe, fittings, valves Pressure. Drop
expansion, contraction, etc. Item in- pS I
Item No. Unit Eq. Ft. Total Eq. Ft. Pipe B Equivalent 5)
1
Pipe 254 4 254 L Ori fi ce 5 1 =10
s
Mator Valve (control 1 740
40
90OElbow
10
8
3
Tee
24
Mi scellaneaus
4
4
1
Gate Va.
Total i -
1
1
1
I
I
Total
f Rounded total to 75 feet !c Estimated line size erif ied)
By difference Actual Velocity 3.9 fp s
Inlet = 350 psig; Outlet = 0 psig Unit Lass per 100 ft. 1.52 Dsi (see below]
Friction Loss = 10 (includes orifice loss)
Balance for Valve = 340 psi Total head loss 869
in feet of liquid
Total pressure
drop in psi 350
Selected pipe sire 14" Material 8 Weight Schedule 40 steel
Calculations: Re = 50.6 QP/ dL= 50.6(25) (0.93 x 62.3)/(1.61) (0.91) = 50,025
b/d = 0.0012; f = :.02: (Figures 2-3 and 2-11)
AP/lOO' = 0,0216 f/3 Q2 / d5 = 0.0216(0.021) (62.3) (0.93) (25)*/(1.65)5
4
= 1.52 psi/lOO ft.
Total Pipe System Friction =((329)(1.52/100)) + 5" = 10 psi for friction; "Orifice
Total Loss, Feet Liquid = 350(2.3lft./psi)(l/0.93) = 869 feet of Liquid
Checked by: Dote:
Figure 2-28. Line sizing sheet for example problem, Example 2-7.

